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abruzzese [7]
3 years ago
6

Given the equation Square root of 2x plus 1 = 3, solve for x and identify if it is an extraneous solution

Mathematics
2 answers:
maksim [4K]3 years ago
6 0
To answer the question above, raise both sides of the equation to the power of two.
(sqrt (2x + 1))² = 3²
This will simplify into,
2x + 1 = 9
Solving for the value of x gives an answer of x = 4. This value is not an extraneous root as it satisfy the original equation even if it is inside the radical sign. (I hope this is right)
krek1111 [17]3 years ago
5 0
Use socratic. Hold up lemme find the answer
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Answer:

Step-by-step explanation:

1)  

2(x – 4) + 32

Multiply it out.

2 * x - 2 * 4 + 32

2x - 8 + 32  

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2)

9x + 4(x + 2) – 5

Multiply it out

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3 years ago
What numbers are divisble by 23 but are between 2 and 10?
zloy xaker [14]
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For a number to be divisible by 23, it has to be greater than 23.

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3 0
3 years ago
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LenKa [72]

Step-by-step explanation:

I am not sure, if something else is missing.

but given that one chart we can say that Craig had 2 fastest throws.

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I assume the upper limit of each interval is included, and the lower limit is excluded.

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3 0
2 years ago
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ANEK [815]

Answer:

Step-by-step explanation:

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5 0
3 years ago
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Irina-Kira [14]
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See if any of these match an answer option.
8 0
3 years ago
Read 2 more answers
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