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abruzzese [7]
2 years ago
6

Given the equation Square root of 2x plus 1 = 3, solve for x and identify if it is an extraneous solution

Mathematics
2 answers:
maksim [4K]2 years ago
6 0
To answer the question above, raise both sides of the equation to the power of two.
(sqrt (2x + 1))² = 3²
This will simplify into,
2x + 1 = 9
Solving for the value of x gives an answer of x = 4. This value is not an extraneous root as it satisfy the original equation even if it is inside the radical sign. (I hope this is right)
krek1111 [17]2 years ago
5 0
Use socratic. Hold up lemme find the answer
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Answer:

P(success at first attempt) = 0.1353

Step-by-step explanation:

This question follows poisson distribution. Thus, the formula is;

P(k) = (e^(-G) × (G)k)/k!

where;

G is number of frames generated in one frame transmission time(or frame slot time)

Let's find G.

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To find the chance of success on the first attempt will be given by;

P(success at first attempt) = P(0) = e^(-G) = e^(-2) = 0.1353

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3 years ago
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3 years ago
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Vilka [71]

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Step-by-step explanation:

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