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abruzzese [7]
2 years ago
6

Given the equation Square root of 2x plus 1 = 3, solve for x and identify if it is an extraneous solution

Mathematics
2 answers:
maksim [4K]2 years ago
6 0
To answer the question above, raise both sides of the equation to the power of two.
(sqrt (2x + 1))² = 3²
This will simplify into,
2x + 1 = 9
Solving for the value of x gives an answer of x = 4. This value is not an extraneous root as it satisfy the original equation even if it is inside the radical sign. (I hope this is right)
krek1111 [17]2 years ago
5 0
Use socratic. Hold up lemme find the answer
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1+4+9+16+25=36+49+64+81+100+121+144=650

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