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Aleks [24]
3 years ago
13

How much would it cost to buy a cover for the pool that costs $0.30 per square foot?

Mathematics
1 answer:
Svetllana [295]3 years ago
5 0
64 hahhahahahahahahhaahhahahahahshshsh
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I don't understand how to do this
Georgia [21]

9514 1404 393

Answer:

  B, E

Step-by-step explanation:

You are give a table of values of x and f(x). You are told that g(x) = (1/2)f(x), and you are asked for points (x, g(x)) that match that description.

It can be useful to mentally, or actually, add a third column to the table that shows the values of g(x). Each of those is half the corresponding value of f(x), because that is what g(x) = (1/2)f(x) means.

Having done that, you can then compare the ordered pairs (x, g(x)) to those in the answer list to see which ones match. The ones that match are highlighted in green in the attachment:

  (-1, -2) . . . . . . 2nd choice

  (6, 3/2) . . . . . 5th choice

3 0
3 years ago
Why is 1/2 not useful as a benchmark to compare 5/8 and 9/10?
pentagon [3]
1/2 would not be a useful benchmark to compare these 2 fractions because both of them are greater than half. The benchmark fraction 1/2 is most useful when one fraction is less than half and the other more than 1/2. 5/8 is more than 4/8(1/2), and 9/10 is more than 5/10(1/2).
4 0
3 years ago
Read 2 more answers
PLEASE PLEASE PLEASE HELP! <br>19 <br>​
dsp73
The answer is D. += up or right ; -= down or left
3 0
3 years ago
12 cookies + 5 cookies take away 10 cookies equals 2
skad [1K]

12 + 5 = 17

17 - 10 = 7

you are false

7 0
4 years ago
Read 2 more answers
A quadrilateral has vertices at A(–5, 5), B(1, 8), C(4, 2), D(–2, –2). Use slope to determine if the quadrilateral is a rectangl
lianna [129]

With the properties of rectangle in mind we must perform two verification. Verify to see if opposite sides are parallel and adjacent sides are perpendicular.

We need to determine the slope of each side, using the formula,

m=\frac{y_2-y_1}{x_2-x_1 }

<u>Slope  of AB</u>

m_{AB}=\frac{8-5}{1--5}

\Rightarrow m_{AB}=\frac{8-5}{1+5}

\Rightarrow m_{AB}=\frac{3}{6}

\Rightarrow m_{AB}=\frac{1}{2}


<u>Slope of BC</u>

m_{BC}=\frac{2-8}{4-1}

\Rightarrow m_{BC}=\frac{-6}{3}

\Rightarrow m_{BC}=-2

<u>Slope of CD</u>

m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-4}{-6}

\Rightarrow m_{CD}=\frac{2}{3}

<u>Slope of AD</u>

m_{AD}=\frac{-2-5}{-2--5}

\Rightarrow m_{AD}=\frac{-2-5}{-2+5}

\Rightarrow m_{AD}=\frac{-7}{3}

<u>Verify Parallel sides</u>

If the quadrilateral is a rectangle, then opposite sides should have the same slope. But

m_{AD} = \frac{-7}{3} \neq m_{BC}=-2

m_{AB}=\frac{1}{2} \neq m_{CD}=\frac{2}{3}


<u>Verify Perpendicularity</u>

And also the product of slopes of all sides with a common vertex should be -1. But

m_{AB} \times m_{BC}=\frac{1}{2} \times -2=-1

m_{AB} \times m_{AD}=\frac{1}{2} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{AD}=\frac{2}{3} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{BC}=\frac{2}{3} \times -2 \neq -1


Since the quadrilateral fails to satisfy all these conditions, the quadrilateral is not a rectangle




6 0
3 years ago
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