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lina2011 [118]
3 years ago
5

21. Name an angle that is adjacent to O ZDGB O ZEGC O ZEGF O ZCGB O ZFGA O ZEGT O ZDGE

Mathematics
1 answer:
olga2289 [7]3 years ago
6 0

Answer:

the answer is D hope this helps you

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What is the perimeter of the square 3 by 3
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Answer:12cm

Step-by-step explanation:3+3+3+3 because its 3x3 so their is 3cm on each side

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Donna is making a cookie recipe that calls for 1 ¾ cups of sugar. However, when she goes to take out the measuring cups she can
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D. 3

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PLZZZZZZZZZ HELP THANK YOUUUUUUUU !!!!!
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Answer:

<u><em>It has gone -160 miles.</em></u>

Step-by-step explanation:

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Victor is thinking of a number. If he multiplies his number by nine and then subtracts 7, he
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3 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
3 years ago
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