This is the answer. Always remember SOH CAH TOA
Had fun solving this ngl
21. Name an angle that is adjacent to O ZDGB O ZEGC O ZEGF O ZCGB O ZFGA O ZEGT O ZDGE
1 answer:
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Answer:
17)
18)
19) 14x³y²
20) π
Step-by-step explanation:
17)
Area of triangle = 1/2*b*h
A = 1/2(4a²b)(3ab)
A = 6(a³b²)
18)
A = 1/2(4mn⁵)(20m³n⁵)
A = (40)(m⁴n¹⁰)
19)
A = 2 (1/2)(2xy)(3x²y)
A = (6x³y²) + (4x²y*2xy)
A = 6x³y² + 8x³y²
A = 14x³y²
20)
A = (3xy³)²
A = 3² x² (y³)²
Answer:
4(x - 1) = 4x - 4
3x + 6 = 3(x + 2)
Step-by-step explanation:
The first equation is
We simplify to get;
This is not true, therefore this equation has no solution.
The second equation is
Combine like terms:
This has a unique solution.
The 3rd equation is
Group similar terms:
The 4th equation is :
This is always true. The equation has infinite solution.
The 5th equation is:
This also has infinite solution
The 6th equation is
It has a unique solution.
Answer:
The 3rd one again
Step-by-step explanation:
(a+−2)(8+−5a+3)
=(a)(8)+(a)(−5a)+(a)(3)+(−2)(8
)+(−2)(−5a)+(−2)(3)
=8−5
+3a−16
+10a−6
=8−21
+13a−6
hope this helped:)