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3 years ago

Which is true of the measures of the sides of the original triangle?

Mathematics

2 answers:

likoan [24]3 years ago

8 0

Answer:

B .Each side of the original triangle is 2 times the length of each side of the scale drawing.

TELL ME IF I'M WRONG I THINK IS B

Step-by-step explanation:

arlik [135]3 years ago

8 0

Answer:

The true of the measures of the sides of the original triangle correspond to option B. Each side of the original triangle is 2 times the length of each side of the scale drawing.

Step-by-step explanation:

The scale is the relationship that exists between the magnitudes of a drawing and the actual dimensions. The scale factor is defined by two numbers that determine the relationship between drawing and reality. The first number of the proportion refers to the drawing on the paper (corresponding to the drawing). The second number of the proportion refers to the reality of the object (real dimensions).

The two numbers are separated by a colon or by the sign of the division /.

A reduction scale is used when the object in the drawing is smaller than in reality, that is, objects are drawn smaller than their actual size. This is the type of scale in this case.

In this case the represented triangle factor is 1/2 indicates that one unit in the drawing equals 2 units in reality. That is, the object is 2 times larger in reality than in the drawing.

So, the true of the measures of the sides of the original triangle correspond to option B. Each side of the original triangle is 2 times the length of each side of the scale drawing.

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If something cost 15$ and he wants to tip 20% how much would it be

ANTONII [103]

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3 years ago

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If 2(4x + 3)/(x - 3)(x + 7) = a/x - 3 + b/x + 7, find the values of a and b.

zmey [24]

Answer:

$a=3$ and $b=5$ .

Step-by-step explanation:

So I believe the problem is this:

$\frac{2(4x+3)}{x-3}(x+7)}=\frac{a}{x-3}+\frac{b}{x+7}$

where we are asked to find values for $a$ and $b$ such that the equation holds for any $x$ in the equation's domain.

So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).

In other words this will clear the fractions.

$\frac{2(4x+3)}{x-3}(x+7)}\cdot(x-3)(x+7)=\frac{a}{x-3}\cdot(x-3)(x+7)+\frac{b}{x+7}(x-3)(x+7)$

$2(4x+3)=a(x+7)+b(x-3)$

As you can see there was some cancellation.

I'm going to plug in -7 for x because x+7 becomes 0 then.

$2(4\cdot -7+3)=a(-7+7)+b(-7-3)$

$2(-28+3)=a(0)+b(-10)$

$2(-25)=0-10b$

$-50=-10b$

Divide both sides by -10:

$\frac{-50}{-10}=b$

$5=b$

Now we have:

$2(4x+3)=a(x+7)+b(x-3)$ with $b=5$

I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.

$2(4\cdot 3+3)=a(3+7)+b(3-3)$

$2(12+3)=a(10)+b(0)$

$2(15)=10a+0$

$30=10a$

Divide both sides by 10:

$\frac{30}{10}=a$

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So $a=3$ and $b=5$ .

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2 years ago

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Simplify ( If possible please show work)

mamaluj [8]

Answer:

x^2y / 4

Step-by-step explanation:

x^4 y^4 / 4x^2 y^3

x^4 / x^2 = x^2 and y^4 / y^3 = y so:

this = x^2y / 4

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3 years ago

I need all the answers

vodomira [7]

I don’t see the questions?!

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2 years ago

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How do you work this problem

ankoles [38]

An easy way is to do it, if you get confused by multiplying fractions, is by turning the fractions into decimals. Since you are trying to find N you want to multiply the 1/5 by the 1/3.

1/5 = 0.2

1/3 = 0.33333333333333333333333333333333

if you multiply those you get 0.06666666666666666666666666666667 which when put into a fraction it equals 1/15

but if you don't want to do that just try to remember that you want to get by itself. and when multiplying fractions in this situation the bottom numbers only matter.. so 5 x 3 = 15 1/15

would you like me to put it in a document to show you?

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3 years ago