Answer:
The answer is "Creates a profile, that permits master-detail relationship".
Explanation:
This relationship provides the relationship between parent and child when masters describe as a parent and information describes a child by which the main item controls the actions of the object of the detail.
- In this relationship, the main object history is destroyed, the detailed object associated with it will also be lost.
- It lists all related information on the details page of the database, and other choices were wrong which can't be defined in the given senior.
<span>public void myMethod(int w, int y, int z) {
</span>int a, b, c, d, e, f, g, h, i, j, k, l;
<span>a = w * z;
</span>b = w * z + y;
c = w * -z;
d = w * --z + y++;
e = w * z-- + ++y<span> ;
</span>f = w + z * y;
g = w – y + z;
h = (w + y) * z;
i = y / w;
j = y / z;
k = w % y;
<span>l = y % w;
</span>System.out.println( "%d %d %d %d %d %d %d %d %d %d %d %d", a,b,c,d,e,f,g,h,i,j,k);
}
To use
myMethod(2, 7, 12);
Answer:
- <u>Abstract Connoisseurs.</u>
- <u>Hypertext Assassins.</u>
- <u>Callback Cats.</u>
- <u>Boolean Autocrats.</u>
- <u>Runtime Terror.</u>
Explanation:
<em><u>Hope it's help you !!</u></em>
Answer:
The answer is letter A. TRUE
Explanation:
The variety of theatre introduced in the 1960s that denotes semi-professional or even amateur theatre in the New York/Manhattan area, often in locations such as church basements, YMCAs, and coffeehouses, is commonly known as off-off-Broadway. This statement is true.
Answer:
Explanation:
bool isPalindrome(string str)
{
int length = str.length();
for (int i = 0; i < length / 2; i++) {
if (str [i] != str [length – 1 – i]) {
return false;
}
}
cout << str << "is a palindrome";
return true;
}
