Answer:
D
Explanation:
The answer is D because if you're looking for lightweight materials, you'll be dealing with chemistry, and chemistry is sience.
That’s not a question but good for her
Answer: suggesting MDM solution and also linking MDM to both the salesforce and sap. More so, integrating SAP with both Salesforce and legacy CRM.
NB: Don't ever integrate legacy CRM to Salesforce
Explanation:
It should be noted that the best recommendation that could be given in order to keep data in synch b/w Salesforce, legacy CRM and SAP is by suggesting MDM solution and also linking MDM to both the salesforce and sap. More so, integrating SAP with both Salesforce and legacy CRM.
NB: Don't ever integrate legacy CRM to Salesforce
Answer:
The program is written using PYTHON SCRIPT below;
N=int(input(" Enter number of Rows you want:"))
M=[] # this for storing the matrix
for i in range(N):
l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))
M.append(l)
print("The 2D Matrix is:\n")
for i in range(N):
print(end="\t")
print(M[i])
W=[] # to store the first non zero elemnt index
T=[] # to store that value is positive or negative
L=len(M[0])
for i in range(N):
for j in range(L):
if (M[i][j]==0):
continue
else:
W.append(j) # If the value is non zero append that postion to position list(W)
if(M[i][j]>0): #For checking it is positive or negative
T.append(+1)
else:
T.append(-1)
break
print()
print("The first Non Zero element List [W] : ",end="")
print(W)
print("Positive or Negative List [T] : ",end="")
print(T)
Explanation:
In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.
It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.
