Answer:
753.98 cubic cm.
Step-by-step explanation:
We have been given that from right circular cylinder with height 10 cm and radius of base 6 cm, a right circular cone of the same height and base is removed.
To find the area of remaining solid we will subtract volume of cone from volume of cylinder.




Upon substituting our given values in the formula we will get,





Therefore, the volume of remaining solid is 753.98 cubic cm.
Step-by-step explanation:
LHS = 5x+y =5(1)+2= 5+2= 7
RHS = 7
since LHS= RHS
LHS = 7x-2y =7(1)-2(2)=7-4=3
RHS = 3
since LHS=RHS
(1, 2) is a solution to the following system of equations.
True
Answer:
D
Step-by-step explanation:
Given that the ratio of side lengths = 8 : 3, then
ratio of volumes = 8³ : 3³ = 512 : 27 → D
Answer: I think the markup is 66.67%
Step-by-step explanation:
So, if the <span>number is between -3 and 3, It couldn't be more than 3, so C isn't the answer. It also doesn't have to be equal to 3.
B, </span><span>|x| < 3, would be your answer.
Hope this helps!</span>