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Vadim26 [7]
3 years ago
6

Problem 3

Mathematics
2 answers:
coldgirl [10]3 years ago
6 0

Answer:

$62.bope this helpsjensbdnd

lukranit [14]3 years ago
3 0
62 dollars left in the tax
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Tim estimates that 60÷5.7 is about 10.Will the actual quotient be greater than 10 explain
Zepler [3.9K]
Well first you can do the problem. So take 60 divided by 5.7. When it is done it will come out to about 10.5263 which is a irrational number. So yes the quotient will be larger than 10.
Hope I helped!
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Stuart paid $ 48.00 for a New tennis racket ,which was 64% of the original price what was the original price of the racket.
Trava [24]
Seventy five dollars hope this could help[
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3 years ago
Which value for x makes the sentence true? 1/10 + x = 1/7
alexandr1967 [171]

Answer:

3/70

Step-by-step explanation:

change 1/10 and 1/7 so the denominator (bottom number) is the same.  1/10= 7/70 and 1/7= 10/70 so you need 3/70 to make the two numbers equal.

6 0
3 years ago
If you borrowed $3,500 to buy a new car at 3% interest and paid it back in 4 years. How much would you pay in interest?
tankabanditka [31]

Answer:

$420

Step-by-step explanation:

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105 per year for 4 years:

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7 0
3 years ago
Solve the system of equations using matrices. Use the Gauss- Jordan elimination method And find a solution set
KATRIN_1 [288]
\begin{gathered} x+y+z=4 \\ x-y-z=0 \\ x-y+z=8 \\ \text{The system using matrix is} \\ \begin{bmatrix}{1} & {1} & {1}, & {4} \\ {1} & {-1} & {-1,} & {0} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix}\rightarrow F2=F2-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix} \\ \rightarrow F3=F3-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F2=-\frac{1}{2}F2 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F3=F3+2F2=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {2,} & {8}{}{}\end{bmatrix}\rightarrow F3=\frac{1}{2}F3 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F2=F2-F3=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \rightarrow F1=F1-F3=\begin{bmatrix}{1} & {1} & {0}, & {0} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F1=F1-F2 \\ =\begin{bmatrix}{1} & {0} & {0}, & {2} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \text{Therefore, the solution is }x=2,\text{ y=-2 and z=4} \end{gathered}

6 0
1 year ago
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