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ivanzaharov [21]
3 years ago
15

Show your work and find the solution to the following system using substitution or elimination:

Mathematics
1 answer:
notsponge [240]3 years ago
4 0
Look at this from comments then you will find your answer, you’ll see why.
y
=
2
x
;
−
1
y
=
5
x
−
7

Rewrite equations:
y
=
2
x
;
−
y
=
5
x
−
7

Step: Solve
y
=
2
x
for y:
y
=
2
x

Step: Substitute
2
x
for
y
in
−
y
=
5
x
−
7
:
−
y
=
5
x
−
7
−
2
x
=
5
x
−
7
−
2
x
+
−
5
x
=
5
x
−
7
+
−
5
x
(Add -5x to both sides)
−
7
x
=
−
7
−
7
x
−
7
=
−
7
−
7
(Divide both sides by -7)
x
=
1

Step: Substitute
1
for
x
in
y
=
2
x
:
y
=
2
x
y
=
(
2
)
(
1
)
y
=
2
(Simplify both sides of the equation)

Answer:
x
=
1
and
y
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Three classes have the same number of students. The teachers compared attendance on one Friday. Mr. Lopez had 92.5% of his stude
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Suppose the number of students in one of the classes is :

x

So ;

Mr.Lopez \:   \: had \:  \:  \frac{92.5}{100}x \\

_________________________________

Mrs.Foster \:  \: had \:  \:  \frac{19}{20} x \\

So :

Mrs.Foster \:  \: had \:  \:  \frac{19 \times 5}{20 \times 5} x \\

Mrs.Foster \:  \: had \:  \:  \frac{95}{100}x \\

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Ms.Kelly \:  \: had \:  \: 0.9x

Ms.Kelly \:  \: had \:  \:  \frac{9}{10} x \\

Ms.Kelly \:  \: had \:  \:  \frac{90}{100} x \\

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Compare :

\frac{95}{100} x >  \frac{92.5}{100} x >  \frac{90}{100} x \\

Thus :

Mrs.Foster’s  \:  \: class \:  > \: Mr.Lopez’s \:  \:  class \:  >  \: Ms.Kelly’s \:  \:  class \\

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Answer:

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Step-by-step explanation:

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p + 99 – 99 = 107 – 99

p = 8

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