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Alex787 [66]
2 years ago
5

Denies is a semester who is making men’s ties fo an event. She uses 3/4 of a yard of fabric per tie. Denies bought 12 yards of f

abric. How many ties can she make
Mathematics
2 answers:
DiKsa [7]2 years ago
8 0

Answer:

I think they can make 16 ties

PSYCHO15rus [73]2 years ago
7 0

Answer:

9 ties

Step-by-step explanation:

You might be interested in
I have $25 all in nickels and dimes. There are twice as many Nickles as dimes. How many of each are there?
Mama L [17]

Answer:

N=250

Step-by-step explanation:

 "twice as many nickels as dimes"     means    N =2D     [eq1]

 "collection of nickels and dimes is worth $25"    means

        5N + 10D = 2500      [eq2]

   (To avoid using decimal points, PLZ express everything in cents.)

Substitution   (substitute N from eq1 into eq2]:

     5(2D) + 10D = 2500

      10D + 10D = 2500

          20D = 2500

            D = 125

      N=2D         [eq1 again]

      N=2(125)

      N=250

Check:

  Is   5(250) + 10(125) = 2500   ?

        1250 +  1250 = 2500   ?

          2500 = 2500   ?yes

7 0
3 years ago
The value of 3^3 + 4^2 = ___.
miss Akunina [59]
<h3>- - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - </h3>

➷  3^{3}  = 27

4^{2} = 16

16 + 27 = 43

The answer is 43.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

7 0
3 years ago
Read 2 more answers
Solve: -15 = -2.7 + t
AVprozaik [17]

-15 = -2.7 + t

add 2.7 to each side

-15+2.7 = -2.7+2.7 +t

-12.3 = t

7 0
3 years ago
Read 2 more answers
Solve log9^5 =7- 3X by graphing. Which equation should be graphed?
olya-2409 [2.1K]

Answer:

y^1 = log5/log9 & y^2 = 7 - 3x

3 0
3 years ago
Read 2 more answers
A screening test for a certain disease is used in a large population of people of whom 1 in 1000 actually have the disease. Supp
sertanlavr [38]

Answer:

P(D/T)=5.05*10^{-6}

Step-by-step explanation:

Let's call D the event that a person has the disease, D' the event that a person doesn't have the disease and T the event that the person tests negative for the disease.

So, the probability P(D/T) that a randomly chosen person who tests negative for the disease actually has the disease is calculated as:

P(D/T) = P(D∩T)/P(T)

Where P(T) = P(D∩T) + P(D'∩T)

So, the probability P(D∩T) that a person has the disease and the person tests negative for the disease is equal to:

P(D∩T) = (1/1000)*(0.005) = 0.000005

Because 1/1000 is the probability that the person has the disease and 0.005 is the probability that the person tests negative given that the person has the disease.

At the same way, the probability P(D'∩T) that a person doesn't have the disease and the person tests negative for the disease is equal to:

P(D'∩T) = (999/1000)*(0.99) = 0.98901

Finally, P(T) and P(D/T) are equal to:

P(T) = 0.000005 + 0.98901 = 0.989015

P(D/T) = 0.000005/0.989015 = 5.05*10^{-6}

8 0
3 years ago
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