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2 years ago

ANSWER ASAP PLEASE T~T

Mathematics

1 answer:

ki77a [65]2 years ago

7 0

Answer:

13, 11, 2, 25, 66, 5, 12, 25, 45

Step-by-step explanation:

Right to Left

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Help please! worth a lot of points! Screenshot included

vlada-n [284]

Answer:

x=44444444444444444444444444444444

Step-by-step explanation:

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2 years ago

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Trivia took some fishbowls to a flea market. In the first hour she sold one-third of them and a third more; in the second hour,

a_sh-v [17]

<span>Number of bowls left after 1 hour = x - x/3 - 1/3 = 2x/3 - 1/3

</span><span> Number of bowls left after 2 hours = (2x/3 - 1/3) - (2x/3 - 1/3)/2 - 1/2 = 2x/6 - 1/6 - 1/2 = 2x/6 - 4/6 = x/3 - 2/3

keep doing this untill u reach 0 bowls left
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2 years ago

What is the measure of OAC

Lady bird [3.3K]

Answer:

27°

Step-by-step explanation:

A tangent meets a radius at 90°

Angles in a trainable sum to 180°
180 - 90 - 63 = 27°

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2 years ago

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Write an equation that is perpendicular to and 3x+y=3 whose y-intercept 5. Anyone please help me, no link just explain how to do

Liula [17]

Answer:

$y = \frac{1}{3}x + 5$

Step-by-step explanation:

By definition, two lines are perpendicular if and only if their slopes are negative reciprocals of each other: $m = - \frac{1}{m_{2} }$ , or equivalently, $m_{1} * m_{2} = -1$ .

Given our linear equation 3x + y = 3 (or y = -3x + 3):

We can find the equation of the line (with a y-intercept of 5) that is perpendicular to y = -3x + 3 by determining the negative reciprocal of its slope, -3, which is $\frac{1}{3}$ .

To test whether this is correct, we can take first slope, $m_{1} = -3$ , and multiply it with the negative reciprocal slope $m_{2} = \frac{1}{3}$ :

$m_{1} * m_{2} = -1$

$-3 * \frac{1}{3} = -1$

Therefore, we came up with the correct slope for the other line, which is $\frac{1}{3}$ .

Finally, the y-intercept is given by (0, 5). Therefore, the equation of the line that is perpendicular to 3x + y = 3 is:

$y = \frac{1}{3}x + 5$

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2 years ago

ANSWER ASAP GIVING BRAILIEST AND STUFF!

MrRissso [65]

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2 years ago

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