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skad [1K]
3 years ago
14

I spent 20 minutes on the treadmill at

Mathematics
2 answers:
suter [353]3 years ago
8 0
If 20 minutes was 25% of your entire workout, your total workout time would be 80 minutes. 25% is one quarter therefore multiply 20 times 4 which equals 80.
Snowcat [4.5K]3 years ago
5 0
Your answer is going to be 80.
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I dont understand this please help​
Alex787 [66]

Answer:

Its asking you which one is greater or less than. Hope this help?

Step-by-step explanation:

6 0
3 years ago
Simplify.<br> 3^2+ (9-8/2)
solmaris [256]

Hi there! Hopefully this helps!

-----------------------------------------------------------------------------------------------------------

Answer: 14.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

First we calculate <u>3 to the power of 2</u> and get 9.

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\/

9 + 9 - \frac{8}{2} = 14.

Now we add<u> 9 + 9</u> to get 18.

18 - \frac{8}{2} = 14.

Then, we<u> divide 8 by 2</u> to get 4.

18 - 4 = 14.

Then we subtract<u> 4 from 18</u> to get.....You guessed it,<u> 14</u>!

3 0
3 years ago
Read 2 more answers
Efectuati ridicarea la putere
KATRIN_1 [288]
What power? ce <span>putere?</span>
8 0
3 years ago
Which function is shown on the graph?
vichka [17]

Answer:

556

Step-by-step explanation:

Because thats the answer

7 0
2 years ago
Construct a circle of any radius, and draw a chord on it. Then construct the radius of the circle that bisects the chord. Measur
Nady [450]

Answer:

Part A: See the image attached. The angle between the radius and the chord will always be 90 degree if the radius is perpendicular to the chord

Part B: There are many ways to prove this and here is mine

Prove OC is perpendicular to AB

We know that ΔAEC≅AED by SSS criteria (SSS criteria is when all three sides of a triangle is equal making them congruent)

to prove this that they apply to the SSS criteria:

m∠ADO=m∠BDO

m∠ADO=90°=m∠BDO

Part C: See the image attached. A radius is perpendicular to a chord when the chord is equally divided in half by the radius.

Part D: There are many ways to prove this and here is mine

Prove OC is perpendicular to AB

AO=BO because AO and BO are both radii

OD≅OD by reflexive theorem

ΔADO≅ΔBDO because they are both right triangle with the hypotenuse and a side

AB≅BC means that OC is perpendicular to AB

If you are still confused then I recommend watching these vdos by khan academy about proving perpendicular radius bisector: https://youtu.be/2NgzruZ4_5c

https://youtu.be/TgDk06Qayxw

Hope this helped bye:)

4 0
3 years ago
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