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3 years ago

I need help!! F(4) I f f(x)=3x-1

Mathematics

1 answer:

Amanda [17]3 years ago

6 0

Answer:

f(4) =11

Step-by-step explanation:

f(x)=3x-1

Let x = 4

f(4)=3*4-1

= 12-1

= 11

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Evaluate the following double integral: xy dA D where the region D is the triangular region whose vertices are (0, 0), (0, 3), (

natulia [17]

Answer:

I= 84

Step-by-step explanation:

for

$I=\int\limits^{}_{} \int\limits^{}_D {x*y} \, dA = \int\limits^{}_{} \int\limits^{}_D {x*y} \, dx*dy$

since D is the rectangle such that 0<x<3 , 0<y<3

$I=\int\limits^{}_{} \int\limits^{}_D {x*y} \, dA = \int\limits^{3}_{0} \int\limits^{3}_{0} {x*y} \, dx*dy = \int\limits^{3}_{0} {x} \, dx\int\limits^{3}_{0} {y} \, dy = x^{2} /2*y^{2} /2 = (3^{2} /2 - 0^{2} /2)* (3^{2} /2 - 0^{2} /2) = 3^{4} /4 = 81/4$

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2 years ago

Convert 36°F to degrees Celsius.

scoray [572]

Answer:

I think once you do the math you'd get 2.22 celsius.

Step-by-step explanation:

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2 years ago

The basketball court at Johnson Elementary School is the shape of a rectangle. It is 92 feet long and 46 feet wide. What is the

padilas [110]

Answer:

The perimeter of the basketball court is <u>276 feet²</u>.

Step-by-step explanation:

Given:

The basketball court at Johnson Elementary School is the shape of a rectangle.

It is 92 feet long and 46 feet wide.

Now, to find the perimeter of the basketball court.

Length = 92 feet.

Width = 46 feet.

So, to get the perimeter we put formula:

$Perimeter=2(length+width)$

$Perimeter=2(92+46)$

$Perimeter=2\times 138$

$Perimeter=276\ feet^2.$

Therefore, the perimeter of the basketball court is 276 feet².

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3 years ago

100 pts Sam purchased a new car for $17,930. The value of the car depreciated by 19% per year. When he trades the car in after x

erik [133]

Answer: 2500

Step-by-step explanation:

I don’t know if it’s right

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2 years ago

What is the area of parallelogram rstu? 21 square units 24 square units 28 square units 32 square units

Ray Of Light [21]

The area of the considered parallelogram RTSU is given by: Option A: 21 sq. units

<h3>How to find the area of a parallelogram?</h3>

Area of a parallelogram = (its height × its base) sq. units.

<h3>What is the distance between two points ( p,q) and (x,y)?</h3>

The shortest distance(length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:

$D = \sqrt{(x-p)^2 + (y-q)^2} \: \rm units$

For this case, the missing diagram is attached below.

If we take the base as ST then as ST is parallel to y axis, the line perpendicular to ST would be parallel to x axis. The heigth of a parallogram is the perpendicular distance between its base and top.

The base is ST and top is RU, the line segment US is perpendicular to both RU and US and its length,therefore, will serve as height as its length=perpendicular distance between the base and the top of the parallelogram.

Thus, we get:

Area of RTSU = Length of ST × Length of US

The coordinates of endpoints of ST are (4,-1), (4,-4)

Thus, the length of ST = distance between S and T = $\sqrt{(4-4)^2 + (-1 - (-4))^2 }= 3$

The coordinates of endpoints of US are (-3,-1), (4,-1)

Thus, the length of US = distance between U and S = $\sqrt{(-3-4)^2 + (-1 - (-1))^2 }= 7$

Thus, Area of RTSU = Length of ST × Length of US = 3 × 7 = 21 sq. units.

Thus, the area of the considered parallelogram RTSU is given by: Option A: 21 sq. units

Learn more about distance between two points here:

brainly.com/question/16410393

3 0

2 years ago