Answer:
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Answer:
λN N(0) = 6
N(t) = N₀e^(λt)
Applying the inital value condition
N(t) = 6e^(λt)
Step-by-step explanation:
Summarizing the information briefly and stating the variables in the problem.
t = time elapsed during the decay
N(t) = the amount of the radioactive substance remaining after time t
λ= The constant of proportionality is called the decay constant or decay rate
Given the initial conditions
N(0) = N₀ = 6
The rate at which a quantity of a radioactive substance decays (
) is proportional to the quantity of the substance (N) and λ is the constant of proportionality is called the decay constant or decay rate :
λN
N(t) = N₀e^(λt) ......equ 1
substituting the value of N₀ = 6 into equation 1
N(t) = 6e^(λt)
We can write the domain and range in interval notation which uses values within brackets to describe a set of numbers in interval notation we use a square bracket [ when the set includes the endpoint and a parenthesis ( to include that the endpoint is either not included or the interval is unbounded for example if a person has $100 to spend he or she would need to express the interval that is more than 0 and less than or equal to 100 and write (0, 100]. We will discuss interval notation in greater detail later
If he need 380 to buy the bike but already has35, the he needs 380-35 = 345 more. if he makes 15 a week delivering papers, divide 345 by 15 to get the number of weeks it will take to save. 345/15=23 23 weeks
