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iogann1982 [59]
3 years ago
6

Find the volume of the figure. Round to the nearest tenth if necessary.

Mathematics
1 answer:
lisov135 [29]3 years ago
8 0

Answer:

Volume = 204 m³

Step-by-step explanation:

The figure is a triangular prism

Volume of the triangular prism = ½ × a × c × h

Where,

a = 8 m

c = 5.1 m

h = 10 m

Plug in the known values and solve

Volume = ½ × 8 × 5.1 × 10

Volume = 4 × 5.1 × 10

Volume = 204 m³

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Find the 64th term of the following arithmetic sequence.<br> 6, 14, 22, 30,
olga55 [171]

Answer:

<h2>510</h2><h2 />

Step-by-step explanation:

30-22=8

22-14=8

14-6=8

then

→ the common difference r = 8

→ the first term = 6

THerefore, (accoriding to the standard explicit formula)

the 64th term = term 1 + (64 - 1)×r

                       = 6 + 63×8

                       = 510

7 0
3 years ago
there were 1000 fish in the lake the first year the next year there were 1750 fish in the lake what is the percent gain
Alexus [3.1K]
The percent gain is 75%.

75% is 750, of 1000. Which means you would’ve gained 75% more.
3 0
3 years ago
Simplify the numerical expression<br> below.<br> -0.625 -3.85 =
Nadya [2.5K]

The Answer Is -4.475

Hope This Help's

4 0
4 years ago
I need help with this asap! Please show how you got the awnser! I WILL MARK BRAINLIEST!!!
Shkiper50 [21]

Answer:

x=15

angle =34

Step-by-step explanation:

find the missing angle

180-146=34

angle=34

so

all angles added together

(5y+3)+(4y+8)+34=180

9y+11+34=180

9y+45=180

9y=135

y=15

8 0
3 years ago
The square based pyramid is cut horizontally at a height of 15cm to leave this frustum. Calulate the volume of the frustum.
allsm [11]

Answer:

The answer is given below

Step-by-step explanation:

The question is not complete. The correct question is:

A square based pyramid have a height of 30 cm and base of 10 cm. The The square based pyramid is cut horizontally at a height of 15cm to leave this frustum.

Answer:

The frustum would have a base of 10 cm and height of 15 cm. The lower base has a length of 10 cm. to calculate the upper base, we use the formula:

\frac{height\ of\ frustum}{height\ of \ pyramid}=\frac{base \of\ upper\ edge}{base \of\ lower\ edge}

Substituting:

\frac{30}{15}=\frac{10}{b} \\ b=15*10/30=5

The volume of the frustum is given by the formula:

V=\frac{h}{3}(A_1+A_2+\sqrt{A_1A_2} )

Where h is the height of the frustum = 15 cm, A1 is the area of the lower base = 10 * 10 = 100 cm², A1 is the area of the upper base = 5 * 5 = 25 cm²

Substituting gives:

V=\frac{h}{3}(A_1+A_2+\sqrt{A_1A_2} )=\frac{15}{3}(100+25+\sqrt{100*25} )= 875\ cm^3

7 0
3 years ago
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