Question

Find the 64th term of the following arithmetic sequence. 6, 14, 22, 30,

Answer 1

Answer:

510

Step-by-step explanation:

30-22=8

22-14=8

14-6=8

then

→ the common difference r = 8

→ the first term = 6

THerefore, (accoriding to the standard explicit formula)

the 64th term = term 1 + (64 - 1)×r

                       = 6 + 63×8

                       = 510