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3 years ago

Find the length line segment between the points (-2,-1) and (5,6)?

Mathematics

1 answer:

snow_lady [41]3 years ago

6 0

Answer:

7√2 units

Step-by-step explanation:

( $x_{1}$ , $y_{1}$ ) and ( $x_{2}$ , $y_{2}$ )

d = $\sqrt{(x_{2} -x_{1} )^2 + (y_{2} -y_{1})^2 }$

( - 2 , - 1 )

( 5 , 6 )

d = $\sqrt{(-2-5)^2 + (-1-6)^2}$ = 7√2 units

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Write a quadratic function that has a vertex of (2,-3) and goes through the point (1,3).

patriot [66]

Answer:

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5 0

3 years ago

antoniya [11.8K]

Answer: 3.51%

Step-by-step explanation:

Percent error is theoretical minus experimental, divided by the theoretical, and multiplied by 100.

$error=(\frac{(T-E)}{T} )*100$

$error=(\frac{(17.1-16.5)}{17.1} )*100$

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3 years ago

In this figure, AB¯¯¯¯¯∥CD¯¯¯¯¯ and m∠3=120°. What is m∠6?

victus00 [196]

Answer:

The m∠6 is 60 °.

Step-by-step explanation:

As given in the figure

AB∥CD and m∠3=120°.

As AB and CD are parallel lines and a transversal line passing through AB and CD .

∠ 3 and ∠6 are same side interior angles .

Now by using the property

When two lines are parallel and tansversal passing through parallel lines than same sides interior angles are supplementary .

Thus

∠3 + ∠6 = 180 °

( m∠3=120° )

120 ° + ∠6 = 180 °

∠6 = 180 ° - 120 °

∠6 = 60 °

Therefore the m∠6 is 60 °.

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3 years ago

Someone help me with my Algebra!

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3 years ago

A random sample of 144 observations has a mean of 20. The population standard deviation is known to equal 4.8. The 95.44% confid

Makovka662 [10]

Answer:

The population mean is 19.2 to 20.8.

Step-by-step explanation:

The formula of Confidence interval is

CI = mean ± z* $\frac{s}{\sqrt{n} }$

where

n = sample size

s = Population standard deviation.

mean = Sample mean

z(α/2) = Two tailed z-value for significance level of .

Given : Confidence level = 95.44% = 0.9544

Significance level = α = 1-0.9544 = 0.0456

Now we Use standard z-value table

z-value for Significance level of 0.0456 :

z(α/2) = z(0.0228) = 1.99 = 2(approximately)

And we are given

n=144

s = 4.8

mean = 20

so the required Confidence interval is

CI = 20± 2* $\frac{4.8}{\sqrt{144} }$

= 20 ± 2* $\frac{4.8}{12}$

= 20 ± (0.8)

= (20-0.8, 20+0.8 )

= (19.2 , 20.8)

Therefore the 95.44% CI value for the population mean of 20 is 19.2 to 20.8.

6 0

3 years ago