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anzhelika [568]
3 years ago
14

What is the solution to the following system?

Mathematics
1 answer:
irakobra [83]3 years ago
8 0

Answer:

None?

Step-by-step explanation:

After using the 4 answers using what I think is (x,y,z) none of the answers were true.

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The equation 2x + 4k − 9 = kx − k + 1 is really a family of equations, because for each value of k, we get a different equation
Olegator [25]
You haven't shared "the given value of x," or, if you have, you haven't drawn attention to it.

Just suppose we were to choose x = 4 as a possible solution and then try to find a value of the parameter k that would make x = 4 an actual solution.

2(4) + 4k - 9 = (4)(4) - (4) + 1

Then 8 + 4k - 9 = 16 - 4 + 1, or       4k - 1 = 13.  Then 4k = 14, and k = 14/4, or (after reduction)  k = 7/2   

If the parameter k equals 7/2, then x = 4 is a solution to the given equation.

To check this out further, start with the proposed solution x = 5 and find k.
3 0
4 years ago
A boy decided to save by an unusual method.He put 1cent, the first week.2cent in the second week,4xent in the third week,8cent i
lesya692 [45]

Answer:

Step-by-step explanation:

for 1st week=1 ¢

for 2nd week= 2¢

for 3rd week= 4¢

for 4th week=8¢

for 5th week=16¢

for 6th week=32¢

for 7th week=64¢

for 8th week=64+64=128¢

for 9th week= 128+128=256¢

for 10th week= 256+256=512¢

.: he saved a total of

1+2+4+8+16+32+64+128+256+512=1023¢

1023¢=1023/100=$10.23

4 0
3 years ago
At the beginning of year 1, Jonah invests $300 at an annual
olga55 [171]

At the beginning of year 6, that means 5 years only have elapsed, thus t = 5.

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$300\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=300\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=300(1.04)^5

6 0
4 years ago
PLEASE HELP PICTURE IS SHOWN
IrinaVladis [17]
I have attached the graph so you can compare but it is graph C.

Hope that helps.

6 0
3 years ago
List the next four multiples of the fraction 7/12
choli [55]
<h2>Hello!</h2>

The answer is:

\frac{14}{12},\frac{21}{12},\frac{28}{12},\frac{35}{12}

<h2>Why?</h2>

Let's explain with an example the definition of a multiple.

Multiple of the number 1 are: 1, 2, 3, 4, 5 and so...

Multiple of the number 3 are: 3, 6, 9, 12, 15 and so...

A multiple of a number is the repeated sum of itself, from the example:

Multiple of the number 1 are: Itself, (1+1), (1+1+1), (1+1+1+1), (1+1+1+1+1) and so...

Therefore,

Multiple of \frac{7}{12} are:

\frac{7}{12} =\frac{7}{12}(itself)=\frac{7}{12}*1 \\\\\frac{14}{12}= \frac{7}{12}+\frac{7}{12}=\frac{7}{12}*2\\\\\frac{21}{12}=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}=\frac{7}{12}*3\\\\\\\frac{28}{12}=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}=\frac{7}{12}*4\\\\\frac{35}{12}=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}=\frac{7}{12}*5

Have a nice day!

4 0
3 years ago
Read 2 more answers
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