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3 years ago

9

Find the area of a trapezoid please help im so lost

1 answer:

Murrr4er [49]3 years ago

5 0

Here, trapezoid is composed of two triangles, and one rectangle.
So, Area of rectangle = 4 * 7 = 28 cm²
Area of a triangle = 1/2 * 3 * 7 = 21/2 = 10.5 cm²

Area of Trapezoid = area of rectangle + 2(area of triangle)
= 28 + 2(10.5)
= 28 + 21 = 49

In short, Your Answer would be 49 cm²

Hope this helps!

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ASHA 777 [7]

Answer:

148-13=135

4x+13= - 3.25

6x+2 = - 0.33

Step-by-step explanation:

1) SIMPLE SUBTRACTION

148

- 13

---------

135

---------

2)

4x+13=0

4x= - 13

x= -13/4

x= - 3.25

3)

6x+2 = 0

6x= -2

x= -2/6

x = -0.33

8 0

3 years ago

Which figure has the same area as the parallelogram shown below? A. A triangle with a base of 4 mm and a height of 20 mm B. A tr

Arisa [49]

<h2>Answer: A trapezoid with bases of 6 mm and 14 mm and a height of 8 mm </h2>

The parallelogram in the figure has an area of $80mm^{2}$ , according to the following formula, which works for all rectangles and parallelograms:

$A_{parallelogram}=(b)(h)$ (1)

Where $b$ is the base and $h$ is the height

The<u> area of a triangle</u> is given by the following formula:

$A_{triangle}=\frac{1}{2}(b)(h)$ (2)

So, for option A:

$A_{triangle}=\frac{1}{2}(4mm)(20mm)=40mm^{2} \neq 80mm^{2}$

Now, the <u>area of a trapezoid </u>is:

$A_{trapezoid}=\frac{1}{2}(b_{1}+ b_{2})(h)$ (3)

For option B:

$A_{trapezoid}=\frac{1}{2}(15mm+25mm)(2 mm)=40mm^{2} \neq 80mm^{2}$

For option C:

$A_{trapezoid}=\frac{1}{2}(6mm+14mm)(8 mm)=80mm^{2}$ >>>>This is the correct option!

For option D:

$A_{rectangle}=(30mm)(8mm)=240mm^{2} \neq 80mm^{2}$

<h2>Therefore the correct option is C</h2>

5 0

2 years ago

Suppose y varies directly as x, and y=14 when x=4. What is the value of y when x=9

Katena32 [7]

Given :-

y varies directly as x, and y=14 when x=4.

To Find :-

the value of y when x=9 .

Solution :-

<u>A</u><u>c</u><u>c</u><u>o</u><u>r</u><u>d</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>o</u><u> </u><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>,</u>

y = kx ( k is constant )

<u>When</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>1</u><u>4</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>4</u><u> </u><u>,</u>

14 = k(4)
k = 14/4
k = 7/2

<u>W</u><u>h</u><u>e</u><u>n</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>9</u><u> </u><u>,</u>

y = 7/2*9
y = 63/2
y = 31.5

8 0

2 years ago

SOLVE STEP BY STEP !!!! answer correctly please !! Will mark brainliest !!!!!!!!!!!!!!

Mnenie [13.5K]

Step-by-step explanation:

(3X-20)+(3X+5)=111(( SINCE 111 IS TOTAL ANGLE

6X-15=111

6X=126

X=21

EFG=3×21-20

=63-20=43

8 0

3 years ago

4c(2x+3) is my question. How to answer?

Shkiper50 [21]

Answer:

8cx + 12c

Step-by-step explanation:

Multiply the parentheses by 4 and then calculate the products

3 0

2 years ago