A pile of sand has a weight of 90kg.
1 answer:
You might be interested in
Start off by combining like terms on the LHS (the terms with x in them).
So we get
Replacing this result with what we had before on the LHS, we get
⇒Solve for x (divide both sides
)
⇒Don't forget about reciprocity rules when dividing. This is the same as multiplying both sides by
⇒
⇒
***This is a proper fraction
So we get
Replacing this result with what we had before on the LHS, we get
⇒Solve for x (divide both sides
⇒Don't forget about reciprocity rules when dividing. This is the same as multiplying both sides by
⇒
⇒
f(x) + n - shift a graph of f n units up
f(x) - n - shift a graph of f n units down
f(x + n) - shift a graph of f n units left
f(x - n) - shift a graph of f n units right.
f(x) = x³, g(x) = (x - 2)³ - 3 = f(x - 2) - 3
2 units right and 3 units down.
