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Lorico [155]
3 years ago
6

How many ways are there to travel in xyz space from the origin (0, 0, 0) to the point (4, 3, 5) by taking steps one unit in the

positive x direction, one unit in the positive y direction, or one unit in the positive z direction? (moving in the negative x, y, or z direction is prohibited, so that no backtracking is allowed.)?
Mathematics
1 answer:
Virty [35]3 years ago
5 0
I would think you would have to walk the 4 spaces out on the X axis. I would then turn and walk 5 spaces on the Z axis before turning up to walk the last 3 steps on the Y axis.

I think any other way would cause you to move in a negative direction. I hope this helps.
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Answer:

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Step-by-step explanation:

Let us revise the rule of the translations

  • If the point (x, y) translated horizontally to the right by h units then its image is (x + h, y) ⇒ T (x, y) → (x + h, y)
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  • If the point (x, y) translated vertically up by k units then its image is (x, y + k)→ (x + h, y) ⇒ T (x, y) → (x, y + k)
  • If the point (x, y) translated vertically down by k units then its image is (x, y - k) ⇒ T (x, y) → (x, y - k)

∵ Point A = (-2, 0)

∵ T (3, 2) → A = B

→ By using the 1st and 3rd rules above, A is translated 3 units right and 2

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∴ T (x, y) → (x + 3, y + 2)

∵ A = (x, y)

∵ x = -2 and y = 0

∴ B = (-2 + 3, 0 + 2)

∴ B = (1, 2)

∴ Point B is (1, 2)

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