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3 years ago

Jeff paid a flat fee of $269.50 for a year's worth of vet visits for

Mathematics

2 answers:

valkas [14]3 years ago

8 0

Answer:

Step-by-step explanation:

269.50 divided by the 14 visits equals the average cost for one visit, or $19.25... which is honestly a fantastic deal lol

Advocard [28]3 years ago

6 0

All I gotta say is DANG THATS A CHEAP VET FOR 4 CATS

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Solve for x -16=8x/5

torisob [31]

-16 = 8x/5......8x/5 is the same as 8/5(x)

-16 = (8/5)x...divide both sides by 8/5
-16 / (8/5) = x
-16 * 5/8 = x
-80/8 = x
-10 = x <===

6 0

3 years ago

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

4 years ago

Please help. I will give ten points for answer

galina1969 [7]

Answer: 2nd graph and the point is (6,7)

Step-by-step explanation:

6 0

3 years ago

Help Me for number 1 & 2

mafiozo [28]

This may not be correct but Georgia will be about nine if u subtract 6 from 15... And as for Jerry, if he swims for 4 hours, at 2 miles, he might be swimming 480 miles.. 2x60 (aka and hour x 2) 120.. Do that 4 times and u end up with about 480.. So sorry if I'm wrong

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4 years ago

Choose all options that apply. Which of the following are equal to 20%? | a) .25 b) 1/5 Oc) 1/10 d) .20

zloy xaker [14]

Answer:

b. and d.

Step-by-step explanation:

$20 = \frac{20}{100} \\ 0.25 = \frac{25}{100} \\ \frac{1}{5} = \frac{20}{100} \\ \frac{1}{10} = \frac{10}{100} \\ 0.20 = \frac{20}{100}$

4 0

3 years ago