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3 years ago

What y’all think helps guysss!!!:((((

Mathematics

2 answers:

nlexa [21]3 years ago

7 0

Answer:

Yes.

Step-by-step explanation: Figure B is just a larger scale of figure A.

Ainat [17]3 years ago

5 0

Answer:

pretty sure it's a yes

Step-by-step explanation:

Did it on khan a few months ago

sorry if I made it wrong, my memory isn't too well right now

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PLEASE HELP , TRYING TO BE ON HONOR ROLL !

borishaifa [10]

Option A

The solution is $(0, \frac{-1}{4})$

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

3x + 6y = 1 ------ eqn 1

x - 4y = 1 ------ eqn 2

We have to find solution to system of equations

We can use substitution method

From eqn 2,

x = 1 + 4y -------- eqn 3

Substitute eqn 3 in eqn 1

3(1 + 4y) + 6y = 1

3 + 12y + 6y = 1

18y = 1 - 3

18y = -2

Divide both sides by 18

$y = \frac{-2}{18}\\\\y = \frac{-1}{4}$

Substitute the above value of y in eqn 3

$x = 1 + 4 \times \frac{-1}{4}\\\\x = 1-1\\\\x = 0$

Thus solution is $(0, \frac{-1}{4})$

8 0

3 years ago

Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:

tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

$Q1 = \frac{14}{4}th$

$Q1 = 3.5th$

This is the average of the 3rd and the 4th element

$Q1 = \frac{1}{2} \times (84 + 91)$

$Q1 = 87.5$

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

$Q3 = 3 \times 3.5th$

$Q3 = 10.5th$

This is the average of the 10th and the 11th element.

$Q_3 =\frac12 \times (98 + 101)$

$Q_3 =99.5$

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

$IQR = Q_3 -Q_1$

$IQR = 99.5 - 87.5$

$IQR = 12$

Also, we have:

$IQR(1.5) = 12 \times 1.5$

$IQR(1.5) = 18$

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

$Lower = 87.5- 18$

$Lower = 69.5$

$Upper = Q_3 + IQR(1.5)$

$Upper = 99.5 + 18$

$Upper = 117.5$

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

6 0

2 years ago

Two divers are swimming at different depths below sea level. One diver is at -25.5 ft. The other diver is at -40.75 ft. How far

-Dominant- [34]

Answer:

66.25 ft

Step-by-step explanation:

25.5 + 40.75

66.25

They are 66.25 feet away from each other.

Please let me know if I'm wrong!

5 0

4 years ago

What is the distance between points (-2, 8) and (6, -2)? Round to the nearest tenth of a unit.

Mama L [17]

So you will have to find the difference between each number so 6--2=8
and 8--2=10. So then I'm guessing you have to round 8 to 10. Sorry if this isn't all correct.

4 0

4 years ago

Solve for x and y. (Geometry) <br> Can you also show the steps of how u did it

Kazeer [188]

Answer:

y = 10

x = 25

Step-by-step explanation:

From the U theorem the sum of these two angles 120+2x+y = 180

same goes for the bottom part too:

2x-y+140 = 180 now add two equations up

120+2x+y + 2x-y+140 = 180 + 180 add like terms (-y will eliminate +y)

4x + 260 = 360 subtract 260 from both sides

4x = 100 divide both sides by 4

x = 25 since the sum of 2x-y+140 = 180 we can find the value of y by replacing x with 25

2*25 - y + 140 = 180

50 - y + 140 = 180 add like terms

190 - y = 180 subtract 190 from both sides

-y = -10 and y = 10

8 0

3 years ago