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Nutka1998 [239]
3 years ago
7

A pyramid is sliced horizontally. What is the shape of the cross section? Question 2 options: circle triangle square rectangle

Mathematics
2 answers:
Paladinen [302]3 years ago
6 0

Answer:

It's (C) square, I got it correct.

Step-by-step explanation:

Lelechka [254]3 years ago
5 0
The shape of the horizontally sliced pyramid is square
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Please answer my question
lakkis [162]

Replace m with each number in the given set and solve for d(m)


m = 0

d(m) = 7-2(0) = 7-0 = 7

m=1

d(m) =7-2(1) = 7-2 = 5

m = 2

d(m) = 7-2(2) = 7-4 = 3

m=3

d(m) = 7-2(3) = 7-6 = 1


The answers in order from smallest to largest are 1, 3, 5,7

The correct answer would be F.

4 0
3 years ago
15 PPOINTSMrs. France, a seventh-grade math teacher, is grading papers. Three students gave the following responses to the same
alina1380 [7]

Answer:student 3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A grocery store’s receipts show that Sunday customer purchases have a skewed distribution with a mean of 27$ and a standard devi
34kurt

Answer:

(a) The probability that the store’s revenues were at least $9,000 is 0.0233.

(b) The revenue of the store on the worst 1% of such days is $7,631.57.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{X}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

\sigma_{X}=\sqrt{n}\sigma

It is provided that:

\mu=\$27\\\sigma=\$18\\n=310

As the sample size is quite large, i.e. <em>n</em> = 310 > 30, the central limit theorem can be applied to approximate the sampling distribution of the store’s revenues for Sundays by a normal distribution.

(a)

Compute the probability that the store’s revenues were at least $9,000 as follows:

P(S\geq 9000)=P(\frac{S-\mu_{X}}{\sigma_{X}}\geq \frac{9000-(27\times310)}{\sqrt{310}\times 18})\\\\=P(Z\geq 1.99)\\\\=1-P(Z

Thus, the probability that the store’s revenues were at least $9,000 is 0.0233.

(b)

Let <em>s</em> denote the revenue of the store on the worst 1% of such days.

Then, P (S < s) = 0.01.

The corresponding <em>z-</em>value is, -2.33.

Compute the value of <em>s</em> as follows:

z=\frac{s-\mu_{X}}{\sigma_{X}}\\\\-2.33=\frac{s-8370}{316.923}\\\\s=8370-(2.33\times 316.923)\\\\s=7631.56941\\\\s\approx \$7,631.57

Thus, the revenue of the store on the worst 1% of such days is $7,631.57.

5 0
3 years ago
A local gym has 2 pricing options:
DerKrebs [107]
You would have to go 25 times to make it worth getting option b
4 0
3 years ago
The theoretical probability of spinning an even number on a spinner is 23. The spinner has 8 even-numbered sections. How many se
meriva

Answer:

there are 12 sections

here is how to do it:

2 8

_ = _

3 x

so you cross multiply

8 x 3 = 2x

24=2x

12=x

Step-by-step explanation:

6 0
3 years ago
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