Question

If you have 36 ft of fencing, what are the bases and side lengths of the different parallelograms you could enclose with the fencing? Consider only whole-number dimensions.

Answer 1

Answer:

$(l,w) = (1,17)$

$(l,w) = (2,16)$

$(l,w) = (3,15)$

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$(l,w) = (9,9)$

Step-by-step explanation:

Given

$P = 36ft$ --- perimeter

$l \to length$

$w \to width$

Required

Possible dimension of different parallelogram

The perimeter is calculated as:

$P=2(l+w)$

So,we have:

$2(l+w)=36$

Divide by 2

$l + w = 18$

Since l and w must be positive integers, the possible dimensions are:

$(l,w) = (1,17)$

$(l,w) = (2,16)$

$(l,w) = (3,15)$

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$(l,w) = (9,9)$