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nika2105 [10]
3 years ago
11

Bari Jay, a gown manufacturer, received an order for prom dresses from China. Her cost is $32 a gown. If her markup based on sel

ling price is 76%, what is the selling price of each gown? (Round your answer to the nearest cent.)
Mathematics
1 answer:
Sveta_85 [38]3 years ago
3 0

Answer:

$56.32

Step-by-step explanation:

Find the selling price by multiplying the original cost by 1.76:

32(1.76)

= 56.32

So, the selling price is $56.32

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Akira's dog will be having four puppies. Akira performs a
ivanzaharov [21]

Answer:

50/50 but i don know how a coin toss could determine birth

Hope i helped

Step-by-step explanation:

5 0
3 years ago
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In a race, the mean time for three runners was 12.4 seconds and the mean
Ne4ueva [31]

Answer:

11.8

Step-by-step explanation:

3(12.4) + 6(11.5) =  37.2 + 69 = 106.2

106.2/9 = 11.8

4 0
3 years ago
The amount Kenyon earns on the sale of a car can be represented by the equation E (p) = 250 +0.02p where E(p) represents the tot
kap26 [50]

Answer:

1) His total commission is $1,234.3

2) The purchase of the car is $24,790.

Step-by-step explanation:

1) 21640*0.02= 432.8+ 250= 682.8

15075*0.02= 301.5+ 250= 551.5

682.8+ 551.5= 1,234.3

2) 745.8- 250= 495.8/ 0.02= 24,790

5 0
3 years ago
Read 2 more answers
Question 8<br> Calculate the difference (4x2 + x - 5) – (5x2 - 1).
Rufina [12.5K]

Answer:

x - 6

Step-by-step explanation:

(4x2 + x - 5) - (5x2 - 1)

According to the order of operations, parenthesis come first so we will solve what is in the parenthesis first.

Then we do the multiplication because it comes before addition and subtraction.

4x2 = 8

Now we have 8 + x - 5

Combine like terms and 8-5=3 so we have 3 + x

Now for the second one.

5x2=10

10-1=9

Subtracting this from the first expression we have:

3+x-9 =

x - 6

7 0
3 years ago
Para embalar una caja se emplea 4,2 m de cinta adhesiva. ?Cuántas cajas se podrán embalar con tres rollos que tienen 3 hm, 7 dam
kompoz [17]

For this case, we perform the conversions:

First roll:

1 \ Hectometer --------> 100 \ meters\\3 \ Hectometer --------> x

x = \frac {3 * 100} {1}\\x = 300 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.

1 -----------> 4.2

c -----------> 300

c = \frac {300 * 1} {4.2}\\c = 71.42857143\\c = 71

You can pack 71 boxes.

Second roll:

1 \ Decametro --------> 10 \ meters\\7 \ Decameter --------> x\\x = \frac {7 * 10} {1}\\x = 70 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.

1 -----------> 4.2

c -----------> 70

c = \frac {70 * 1} {4.2}\\c = 16.66666667\\c = 16

You can pack 16 boxes.

Third roll:

1 -----------> 4.2

c -----------> 50

c = \frac {50 * 1} {4.2}\\c = 11.9047619\\c = 11

You can pack 11 boxes.

Thus, in total you can pack11 + 16 + 71 = 98 \ boxes

Answer:

98 boxes

4 0
3 years ago
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