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creativ13 [48]
3 years ago
5

If f(x)= -3x -2 and g(x) 2x+1 find (f+g)(x)

Mathematics
1 answer:
olga55 [171]3 years ago
7 0

Answer: x-3

Step-by-step explanation:

Answer: x-3. Step-by-step explanation: f(x) = 3x-2 . g(x) = 2x + 1 (f-g)(x) = 3x-2 - ( 2x+1) Distribute the minus sign =3x-2 -2x-1. Combine like terms

Hope this helps

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How would you solve for the question below???<br> step by step please and thanks.
Airida [17]

Combine the two equations in the right amounts to eliminate y :

-2 (2x + 3y) + (3x + 6y) = -2 (17) + 30

-4x - 6y + 3x + 6y = -34 + 30

-x = -4

x = 4

Solve for y :

2x + 3y = 17

8 + 3y = 17

3y = 9

y = 3

3 0
2 years ago
Multipy the expreshions (2h+2.7) (2h-27)​
Musya8 [376]

Answer:

4h^2-48.6h-72.9

Step-by-step explanation:

(2h+2.7) (2h-27)\\4h^2-54h+5.4h-72.9\\4h^2-48.6h-72.9

5 0
3 years ago
A simple impact crater on the moon has a diameter of 15 kilometers. a complex impact crater has a radius of 30 kilometers. how m
timurjin [86]
The general equation for computing the circumference of a circle is C=\pi d, where C is the circumference, and d is the diameter. (You might also see the equation as C=2 \pi r where r is the radius, because d=2r)

Computing the circumferences of the two circles, we get:
C_{d=15}=\pi (15)=15\pi
C_{d=30}=\pi (30)=30\pi.

To calculate the ratio of two numbers, we can divide one by the other. You can look at this as "How many times does the denominator fit in the numerator?"
\frac{C_{d=30}}{C_{d=15}}=\frac{30\pi}{15\pi}=2
So the circumference of the complex impact crater is 2 times greater than the circumference of the simple impact crater.
7 0
3 years ago
If military time is 0145, what time is it on a regular clock
fenix001 [56]
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4 0
3 years ago
Find the product (b-2at^2)(3b-3at^2)
Maurinko [17]

Answer: 3b^2-9bat^2+6a^2t^4

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

- Apply the Distributive property.

- Remember that, according the exponents properties, when you multiply two powers with equal base, you must add the exponents.

- Add the like terms.

Therefore, you obtain that the product is the following:

(b-2at^2)(3b-3at^2)=3b^2-3bat^2-6bat^2+6a^2t^4=3b^2-9bat^2+6a^2t^4

8 0
3 years ago
Read 2 more answers
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