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3 years ago

Area of a circle 6ft

Mathematics

2 answers:

Neko [114]3 years ago

8 0

R≈1.38 !!!!!!!!!!!!!!
A= 6 ft

slava [35]3 years ago

4 0

Answer:

Step-by-step explanation:

What do you want us to figure out? Did you forget the picture?

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2. Yahir was going up the stairs when he noticed that the first step was taller, so he measured

goblinko [34]

Answer:

6.5

Step-by-step explanation:

This answer makes sense because i subtracted the 8 inches from the total 60 then i used the number i got in the result (52)then i divided 52 by 8 wich are the rest of the steps. getting 6.5

3 0

3 years ago

How can you order a ladder

NikAS [45]

An adult can go online and search for the kind of ladder needed. Then they can choose the store they prefer. After that, they would decide what payment method to use. Shipping information would be entered, or they would go pick it up.

3 0

3 years ago

Read 2 more answers

Is the number 5 prime, composite, or neither?

OlgaM077 [116]

Answer:

A number that is divisible only by itself and 1

therefore 5 is a prime number

3 0

3 years ago

Read 2 more answers

Assume that a cross is made between a heterozygous tall pea plant and a homozygous short pea plant. Fifty offspring are produced

Butoxors [25]

Answer:

1) $\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

2) $df = c-1 = 2-1$

Where c represent the number of categories c=2

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Tall =30 , Short =20

We need to conduct a chi square test in order to check the following hypothesis:

H0: The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.

H1: The deviations from a 1:1 ratio (25 tall and 25 short) are NOT due to chance.

Part 1

So then we know that the expected values would be 25 for each case

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

And if we replace we got:

$\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

Part 2

For this case the degreed of freedom are given by:

$df = c-1 = 2-1$

Where c represent the number of categories c=2

And we can calculate the p value given by:

$p_v = P(\chi^2_{1} >2)=0.157$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(2,1,TRUE)"

7 0

4 years ago

Solve: -8a+ 6(a+7)=1

Pavel [41]

20.5 i used math.way

4 0

3 years ago