-2=-5t+10+2t Solving linear equation Please help me ASAP

Mathematics

1 answer:

Ganezh [65]3 years ago

3 0

Step-by-step explanation:

-2-10=-5t+2t

-12=-3t

minus minus will be cancelled.

so,

12/3=4

You might be interested in

Over the course of 4 days the price of stock at a corporation fell $28. What was the average change in stock price per day?

bezimeni [28]

7 is the average stock change

5 0

3 years ago

Please help me! I need this asap (I was supposed to do it yesterday :/ )<br> Its in the picture UwU

FromTheMoon [43]

Answer:

Hewo!

Step-by-step explanation:

im not sure of the answer but i got the trick!

so for the length add 8 to the width and for the area multiply the width by 14

This should get you the correct answers :)

Hope i helped! :D

3 0

3 years ago

6q + 9 ≤ 9 and 6q + 9 ≥ −9

Ilya [14]

Hello there!

6q + 9 ≤ 9

Start by subtracting 9 from both sides

6q + 9 - 9 ≤ 9 - 9

6q ≤ 0

Then divide both sides by 6

6q/6 ≤ 0/6

q ≤ 0

--------------

The second equation
6q + 9 ≥ -9

Start by subtracting 9 from both sides

6q + 9 - 9 ≥ -9 - 9

6q ≥ -18

Divide both sides by 6

6q/6 ≥ -18/6

q ≥ -3

Good luck with your studies!

7 0

3 years ago

Read 2 more answers

How do you solve this? (#11/#12)

zepelin [54]

$\text{If}\ x_1,\ \text{and}\ x_2\ \text{are zeros of a polynomial function, then the function}\\\text{has equation}:\\\\f(x)=a(x-x_1)(x-x_2).\\----------------------------\\\\11.\ \text{We have the zeros}\ 3\ \text{and}\ i:\\\\f(x)=(x-3)(x-i)=(x)(x)+(x)(-i)+(-3)(x)+(-3)(-i)\\\\=x^2-xi-3x+3i=\boxed{x^2-(3+i)x+3i}\\\\12.\ \text{We have the zeros}\ -2\ \text{and}\ 2i:\\\\f(x)=(x-(-2))(x-2i)=(x+2)(x-2i)\\\\=x^2-(2i)^2=x^2-2^2i^2=x^2-4(-1)=\boxed{x^2+4}\\\\\text{used}\\\\(a-b)(a+b)=a^2-b^2\\\\i=\sqrt{-1}\to i^2=-1$

3 0

3 years ago

I need help very bad please. You guys can do any questions just tell me the number

Andrews [41]

Question 10: P=28cm

if l=8 and w=6

Then (8+6)=14
2(14) so 14x2 = 28
So therefore P=28cm

6 0

4 years ago