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drek231 [11]
3 years ago
6

You are planning on making 250 liters of chili for a big fundraiser you are throwing. You want the

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
7 0

Answer:

30%

Step-by-step explanation:

because you use %

so that is why i think but i am not sure

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Please help math
Naddika [18.5K]
   
\displaystyle\\
15(2a - 2) = 5(a^2 -1) \\  \\ 
30a - 30 = 5a^2-5\\\\
-5a^2 + 30a -30 + 5 =0\\\\
-5a^2 + 30a -25 =0 ~~~~~\Big| \times (-1) \\\\
5a^2 - 30a +25 = 0~~~~~\Big| : 5 \\\\
a^2 - 6a +5 = 0 \\  \\ 
a_{12}= \frac{-b\pm \sqrt{b^2-4ac}}{2a}= \frac{6\pm \sqrt{36-20}}{2}= \frac{6\pm \sqrt{16}}{2}=\frac{6\pm 4}{2}= \boxed{3\pm 2} \\  \\ 
a_1 = 3+ 2 = \boxed{5}\\\\
a_2 = 3-2 = \boxed{1}



8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20%2816%20%2B%204p%29%20%3D%20" id="TexFormula1" title=" \frac{1}{4}
Leviafan [203]
Hopefully this helps :D

7 0
2 years ago
Problem #32 <br> I am not sure if I did this right can you check please and explain
Natasha2012 [34]

Answer:

Step-by-step explanation:

It seems you got the right answer, but didn’t do the problem correctly.

The square root of 2 times the square root of 2 is 2. And then 6 times the square root of two minus the product of 6 and the square root of two equals zero. And then obviously 6 and -6 equals -36. So 2+-36 is -34

6 0
2 years ago
Please help it is due today
just olya [345]

i think answer is 8in2

please talk me my answer is correct or not

8 0
2 years ago
Read 2 more answers
2. Write a quadratic function that has -intercepts (- 3, 0) and (4, 0) and passes through the point (5, 8)
Reptile [31]

Answer:

f(x)=x^2-x-12

Step-by-step explanation:

<u>Quadratic Function</u>

Standard Form of Quadratic Function

The standard representation of a quadratic function is:

f(x)=ax^2+bx+c

where a,b, and c are constants.

When the zeros of f (x1 and x2) are given, it can be written as:

f(x)=a(x-x1)(x-x2)

Where a is a constant called the leading coefficient.

We are given the two roots of f: x1=-3 and x2=4, thus:

f(x)=a(x+3)(x-4)

We also know that f(5)=8, thus:

f(5)=a(5+3)(5-4)=8

Operating:

a(8)(1)=8

Solving:

a=1

The function is:

f(x)=1(x+3)(x-4)

Operating:

\boxed{f(x)=x^2-x-12}

5 0
2 years ago
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