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HACTEHA [7]
2 years ago
6

Can someone be my friend

Mathematics
2 answers:
marta [7]2 years ago
7 0

Answer: yes

Step-by-step explanation:

Artemon [7]2 years ago
4 0

Why is this math, I too think math is the only way to find friendship.

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A gift box in the shape of a rectangular prism measures 8 inches by 8 inches by 10 inches what is the least amount of wrapping p
Phantasy [73]
The first thing we must do for this case is to find the surface area of the rectangular prism.
 We have then:
 A = 2 * (l * h) + 2 * (h * w) + 2 * (w * l)
 Where,
 w: width
 l: long
 h: height
 Substituting values we have:
 A = 2 * (10 * 8) + 2 * (8 * 8) + 2 * (8 * 10)
 A = 448 in ^ 2
 Answer:
 
the least amount of wrapping paper needed to wrap the gift box answer is:
 
A = 448 in ^ 2
5 0
3 years ago
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How to classify 8x4 + 7x3 + 5x2 + 8 by number of terms.
Arisa [49]

Answer:

This is a polynomial.

Step-by-step explanation:

A monomial is a constant, a variable or the product of constants and variables.  

A binomial is the sum or difference of two monomials.

A trinomial is the sum or difference of three monomials.

Anything more than three terms makes it a polynomial.

This has 4 terms; thus it is a polynomial.

4 0
3 years ago
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every prime number greater than 10 has a digit in the ones place that is included in which set of numbers below?
stich3 [128]
So we can start with the full of possibilities and eliminate them one by one.

The full set is {0,1,2,3,4,5,6,7,8,9}.

Now we know that any prime greater than 2 is odd as otherwise it would have 2 as a factor, so we can eliminate all of these digits that would be an even number, leaving:

{1,3,5,7,9}

We also know that any prime greater than 5 cannot be a multiple of 5 and that all numbers with 5 in the digits are a multiple of 5, so we can eliminate 5.

{1,3,7,9}

We know that 11,13,17 and 19 are all primes, so we cannot eliminate any more of these, leaving the set:

{1,3,7,9} as our answer.
8 0
3 years ago
Find the volume.!!.!
zhuklara [117]

Answer:

The image is blurry for me

Step-by-step explanation:

7 0
2 years ago
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Mike just hopped on the edge of a merry-go-round. What are his linear and angular speeds if the diameter of the merry-go-round i
dsp73

Step-by-step explanation:

Given that,

The diameter of the merry-go-round, d = 14 feet

Time taken, t = 6 seconds

Radius, r = 7 feet

The linear speed of the merry-go-round is given by :

v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 7}{6}\\\\=7.33\ m/s

Also,

v=r\omega

Where

\omega is the angular speed

So,

\omega=\dfrac{v}{r}\\\\\omega=\dfrac{7.33}{7}\\\\=1.04\ rad/s

Hence, his linear and angular speeds are 7.33 m/s and 1.04 rad/s.

8 0
3 years ago
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