Question

How to do row of circles in phyton programming ?

Answer 1

Answer:

STEP 1:-

Initialize the number of rows and columns.

for example:-

rows =7

columns=5

 

STEP 2:-

Nest two for loops. outer for loop will iterate rows and inner for loop will iterate columns.

Syntax of nesting two for loops

here i and j are iterators.

for i in range(0,row):

   for j in range(0,col):

STEP 3:-

Now we will use proper condition to print circle

condition 1:- to print ‘*’at first and last column but not at first and last row,

condition2:-to print ‘*’at first and last rows but not at first and last columns.

if the above two conditions are not satisfied then print space (‘ ‘).

code to implement all conditions as follows:-

if((j == 0 or j == columns-1) and (i!=0 and i!=rows-1)) :

    print('*',end='')

elif( ((i==0 or i==row-1) and (j>0 and j<columns-1))):

    print('*',end='')

else:

    print(end=' ')

EXAMPLE

Example to print circle pattern using ‘*’ is as follows

row =6

col=4

for i in range(0,row):

   for j in range(0,col):

       if((j == 0 or j == col-1) and (i!=0 and i!=row-1)) :

           print('*',end='')   #end='' so that print statement should not change the line.

       elif( ((i==0 or i==row-1) and (j>0 and j<col-1))):

           print('*',end='')

       else:

           print(end=' ')  #to print the space.

   print()  #to change the line after iteration of inner loop.

output:-

**  

*  *

*  *

*  *

*  *

**

Explanation: