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hjlf
3 years ago
8

Please someone participate in my typing race ...

Computers and Technology
1 answer:
dsp733 years ago
8 0

Answer:

what is typing race

this link can not be clicked

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Monster Collector
Lera25 [3.4K]

Answer:

In java:

import java.util.*;

public class Main{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 int monsternum, usernum;

 int count = 0;

 Random rand = new Random();

 String [] monsters = {"wild pikamoo","wild bulbaroar"};

 for(int i =0;i<2;i++){

     monsternum = rand.nextInt(5);  

     System.out.print("A "+monsters[i]+" appears! Guess a number between 1 and 5: ");

     usernum = input.nextInt();

     if(monsternum == usernum){      count++;      System.out.println("Congratulations, you caught a "+monsters[i]+"!");  }

 else{      System.out.println("You almost had it, but the monster escaped.");  }

 

 }

 System.out.println("There are no more monsters to encounter!");

 System.out.println("You caught "+count+" monsters of 2");

 if(count!=2){      System.out.print("Keep training to be the very best!");  }

 else{      System.out.print("You're the monster collector master!");  }

}

}

Explanation:

This declares monster and user number as integers

 int monsternum, usernum;

Initialize count to 0

 int count = 0;

Call the random object

 Random rand = new Random();

Create a string array to save the monster names

 String [] monsters = {"wild pikamoo","wild bulbaroar"};

Iterate for the 2 monsters

 for(int i =0;i<2;i++){

Generate a monster number

     monsternum = rand.nextInt(5);  

Prompt the user to take a guess

     System.out.print("A "+monsters[i]+" appears! Guess a number between 1 and 5: ");

Get user guess

     usernum = input.nextInt();

If monster number and user guess are equal, congratulate the user and increase count by 1

<em>      if(monsternum == usernum){      count++;      System.out.println("Congratulations, you caught a "+monsters[i]+"!");  } </em>

If otherwise, prompt the user to keep trying

<em>  else{      System.out.println("You almost had it, but the monster escaped.");  }  </em>

<em>  } </em>

Print no monsters again

 System.out.println("There are no more monsters to encounter!");

Print number of monsters caught

 System.out.println("You caught "+count+" monsters of 2");

Print user score

<em>  if(count!=2){      System.out.print("Keep training to be the very best!");  } </em>

<em>  else{      System.out.print("You're the monster collector master!");  } </em>

5 0
3 years ago
Which of the following is the largest unit of information?
Mila [183]
What are the choices?

5 0
4 years ago
Read 2 more answers
Inputs to a system that can enhance performance is called
disa [49]
Inputs to a system that can enhance performance is called Resources
6 0
3 years ago
Read 2 more answers
Write a recursive function sumAll that accepts an integer argument and returns the sum of all the integers from 1 up to the numb
slavikrds [6]

Answer:

int sumAll(int n)//function definition.

{

   if(n==1)//if condition.

   return 1;

   else//else condition.

   {

       return n+sumAll(n-1);//return the value and call the function in recursive manner.

   }

}

Explanation:

  • The above-defined function is a recursive type function that is written in the c language, which holds the if and else condition.
  • When the user passes the largest value from 1, then the else condition will be executed which adds the largest value and pass the value after the decrement of the value as an argument.
  • When the value will become 1, then the function if-block will be executed which returns the value and ends the calling function recursively.
8 0
3 years ago
Reversing the elements of an array involves swapping the corresponding elements of the array: the first with the last, the secon
Alja [10]

Answer:

// Assume that all variables a, n, temp have been declared.

 // Where a is the array, n is the array length, temp is a temporary

 // storage location.

 // Cycle through the array a.

 // By the time the loop gets halfway,

 // The array would have been reversed.

 // The loop needs not get to the end of the array.

 // Hence, the loop ends halfway into the array i.e n/2.

 for (int k = 0; k < n / 2; k++) {

   

  // Swap first and last, second and next-to-the-last and so on

  temp = a[k];

  a[k] = a[n - k - 1];

  a[n - k - 1] = temp;

 }

Explanation:

Explanation has been given in the code in form of comments. Please go through the comments in the code carefully.

Hope this helps!

6 0
3 years ago
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