Answer:
Step-by-step explanation:
Hello, please consider the following.
We have two equations:
(1) -2x - 4y = 20
(2) -3x + 5y = -25
5*(1)+4*(2) gives
-10x - 20y -12x + 20y = 100 - 100 = 0
-22x = 0
x = 0
I replace in (1)
-4y = 20
y = -20/4 = -5
There is one solution x = 0, y = -5
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
The best way to solve is by using elimination method.
20x = -58 - 2y
17x = -49 - 2y
Multiply second equation by -1
20x = -58 - 2y
-17x = 49 + 2y
Add equations.
3x = -9
Divide.
x = -3
Plug in -3 into one of the equations.
17(-3) = -49 - 2y
-51 = -49 - 2y
Add 49 to both sides.
-2 = -2y
Divide.
1 = y
So your solution is (-3, 1).
I hope this helps love! :)
Answer:
option C is your right answer
Step-by-step explanation:
have a nice day!!
Answer:
The Answer is C
Step-by-step explanation:
3x-4y=5
2x+4y=-3
This equation is the answer to this problem because just by looking at it, you can immediately cancel out the y value and solve for x.
The other equations are wrong because their is extra work needed to eliminate the values.
<h3>
Step-by-step explanation:</h3>
<u>Pythagorus theorum:</u>
9² = 3² + YZ²
81 - 9 = YZ²
√72 = YZ
∴YZ= 8.48 ≈ 8.5
<u>Trigonometry:</u>
We have adjacent as 3, and hypotenuse as 9
cos X = 3/9
X= cos∧-1 (3/9) → <em>[cos inversed]</em>
∴X= 70.5°
We have opposite as 3 and hypotenuse as 9
sin Z= 3/9
Z= sin∧-1 (3/9)→<em> [sin inversed]</em>
∴Z= 19.47 ≈ 19.5
