The temperature outside changed from 82°F to 46°F over a period of six days. If the temperature changed by the same amount
2 answers:
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1. Mean.
2. <span>Standard deviation.
First we have to square each value and calculate the mean of that squares:
so the variance:
and the standard deviation:
</span>
2. <span>Standard deviation.
First we have to square each value and calculate the mean of that squares:
so the variance:
and the standard deviation:
</span>
His percentage of change in the amount of quarts is 82.22%.
Initial amount of lemonade = 45 quart
End amount of lemonade = 8 quart
Change in amount = 45 - 8
= 36
Percent =
=
= 0.8222 * 100
= 82.22%
Hence, his percentage of change is 82.22%.
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