Answer:
umm let me look at this one more time then I will answer:)
ANSWER:
Let t = logtan[x/2]
⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx
⇒dt = 1/2 cos² x/2 × cot x/2dx
⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx
⇒dt = 1/2 cosx/2 / sin x/2 dx
⇒dt = 1/sinxdx
⇒dt = cosecxdx
Putting it in the integration we get,
∫cosecx / log tan(x/2)dx
= ∫dt/t
= log∣t∣+c
= log∣logtan x/2∣+c where t = logtan x/2
Answer:
A
Step-by-step explanation:
The diagonals of a parallelogram bisect each other. Hence, the two shorter sides created on diagonal RT ("6x-7" and "x+28" ) are equal.
<em>We can set them equal and solve for x:</em>
<em>
</em>
<em />
<em>So the side length of 6x -7 is:</em>
<em>6(7)-7 = 35</em>
<em>and the side length of x + 28 is:</em>
<em>7 + 28 = 35</em>
<em />
<em>THus, the diagonal RT = 35 + 35 = 70 units</em>
<em />
<em>Answer choice A is right.</em>
if your wondering what 7 times 3073 is then your answer is 21511. If your looking for something else I don't understand it then. Hope this helps!
Answer:
(a) Test statistic is -2.85 and p-value is 0.0022
(b) Reject the null hypothesis. The population mean of dissolved oxygen content is not equal to 10 mg/L
Step-by-step explanation:
H0: mu equals 10
Ha: mu not equals 10
The test is a two-tailed test because the alternate hypothesis is expressed using not equal to
(a) Test statistic (z) = (sample mean - population mean) ÷ (sd/√n) = (9.14 - 10) ÷ (2/√44) = -0.86 ÷ 0.302 = -2.85
Cumulative area of the test statistic = 0.9978
p-value = 2(1 - 0.9978) = 2(0.0022) = 0.0044
(b) The critical value using 0.02 significance level is 2.422. For a two-tailed test, the region of no rejection of the test statistic lies between -2.422 and 2.422.
Conclusion:
Reject the null hypothesis because the test statistic -2.85 falls outside the region bounded by the critical values -2.422 and 2.422.
The population mean of dissolved oxygen content is not equal to 10 mg/L
