Let the width path be x.
Length of the outer rectangle = 26 + 2x.
Width of the outer rectangle = 8 +2x.
Combined Area = (2x + 26)*(2x + 8) = 1008
2x*(2x + 8) + 26*(2x + 8 ) = 1008
4x² + 16x + 52x + 208 = 1008
4x² + 68x + 208 - 1008 = 0
4x² + 68x - 800 = 0. Divide through by 4.
x² + 17x - 200 = 0 . This is a quadratic equation.
Multiply first and last coefficients: 1*-200 = -200
We look for two numbers that multiply to give -200, and add to give +17
Those two numbers are 25 and -8.
Check: 25*-8 = -200 25 + -8 = 17
We replace the middle term of +17x in the quadratic expression with 25x -8x
x² +17x - 200 = 0
x² + 25x - 8x - 200 = 0
x(x + 25) - 8(x + 25) = 0
(x+25)(x -8) = 0
x + 25 = 0 or x - 8 = 0
x = 0 -25 x = 0 + 8
x = -25 x = 8
The width of the path can not be negative.
The only valid solution is x = 8.
The width of the path is 8 meters.
Answer: our fruitful chance
Step-by-step explanation:
The answer is Cubic. Hope that helps! :D
Answer: the maximum number of guests that he can invite would be 9
Step-by-step explanation:
Darnel's retirement party cost $33, plus an additional $1 for each guest he invites. Assuming Darnel wants to invite x guests to his retirement party, the total amount of money that Darnel would spend is
33 + x
if darnel can afford to spend a total of $42 on his retirement party, then
42 = 33 + x
x = 42 - 33 = 9
Answer:
y = -3x-1
Step-by-step explanation:
all u had to do was plug it into y = mx+b
