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Musya8 [376]
3 years ago
8

Need these two answerd plz help

Mathematics
2 answers:
alexira [117]3 years ago
6 0

Answer:

the pic is block

Step-by-step explanation:

OLga [1]3 years ago
5 0

Answer:

It wont allow anyone to see it.

Step-by-step explanation:

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find the exact volume of the cone above by leaving it in the terms of pi. A. 45picm^3 B. 25picm^3 C. 3.75picm^3 D. 15picm^3
ratelena [41]

Answer:

Step-by-step explanation:

were is the pic just tel the width, height, base

4 0
2 years ago
What's the area of 47 km in 34 km?
EastWind [94]

L x W = A  


47 x 34 = 1598 KM

4 0
4 years ago
Read 2 more answers
Identify the graph of the solution set of -2.3< 4 + 0.9y
aleksandrvk [35]
The answer is A assuming that the 7 is negative cause its on the left side of the 0 but I am positive the answer is A
8 0
3 years ago
Find the measure of arc DF (with an explanation of how to solve please!)
allochka39001 [22]

Answer:

mDF = 90°

(Assuming arc mCE is 5x + 10)

Step-by-step explanation:

When we have two chords crossing in a circle, there is a property where the angle in the cross point is equal half the sum of the corresponding arcs.

So in this case, we have:

70° = (mCE + mDF)/2

Assuming mCE is 5x + 10, we have:

70 = (5x + 10 + 11x + 2)/2

70 = (16x + 12)/2

70 = 8x + 6

8x = 64

x = 8

So the arc mDF is:

mDF = 11x + 2 = 11 * 8 + 2 = 90°

4 0
3 years ago
Find the standard deviation. Round to the nearest tenth. 1, 2, 11, 8, 16, 16,20, 16, 18 OA. 6.5 O B. 6.9 O C. 1.5 ? D. 7.4
NikAS [45]

Answer:

A. 6.5

Step-by-step explanation:

First we find the average  \bar{x} of the 9 data:

\bar{x} =\frac{\sum_{x=1}^{n}x_{i}}{n}

Where n is the data number, that in this case is 9.

\bar{x} =\frac{1+ 2+ 11+ 8+ 16+ 16+20+ 16+ 18}{9}=12\\

The formula of the standard deviation \sigma is:

\sigma=\sqrt{\frac{\sum_{x=1}^{n}(x_{i}-\bar{x})^{2}}{n}}

We replace the data and find the value of the standard deviation:

\sigma=\sqrt{\frac{(1-12)^{2}+(2-12)^{2}+(11-12)^{2}+(8-12)^{2}+(16-12)^{2}+(16-12)^{2}+(20-12)^{2}+(16-12)^{2}+(18-12)^{2}}{9}}

\sigma=\sqrt{\frac{(-11)^{2}+(-10)^{2}+(-1)^{2}+(-4)^{2}+(4)^{2}+(4)^{2}+(8)^{2}+(4)^{2}+(6)^{2}}{9}}=6,54

We approximate the number and the solution is 6,5

6 0
4 years ago
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