Find the lengths of AB,BC,PQ,and QR. Which segments have equal lengths?

vodomira [7]

Picture is too tiny I can’t see

7 0

3 years ago

Sofia is driving to Texas. She travels at 70 kilometers per hour for 2 hours, and 63 kilometers per hours for 5 hours. Over 7 ho

Vladimir79 [104]

Answer:

65 kph

Step-by-step explanation:

There were a total of 7 hours. So two hours were at 70 and the other 5 hours at 63: the equation would be: (70+70+63+63+63+63+63)/7=65

4 0

3 years ago

a certain pharmaceutical company know that, on average 4% of a certain type of pill has an ingredient that is below the minimum

FinnZ [79.3K]

Using the binomial distribution, it is found that there is a 0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

For each pill, there are only two possible outcomes, either it is acceptable, or it is not. The probability of a pill being acceptable is independent of any other pill, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

The sample has 20 pills, hence $n = 20$ .

100 - 4 = 96% are acceptable, hence $p = 0.96$

The probability that fewer that 5 in a sample of 20 pills will be acceptable is:

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{20,0}.(0.96)^{0}.(0.04)^{20} = 0$

$P(X = 1) = C_{20,1}.(0.96)^{1}.(0.04)^{19} = 0$

$P(X = 2) = C_{20,2}.(0.96)^{2}.(0.04)^{18} = 0$

$P(X = 3) = C_{20,3}.(0.96)^{3}.(0.04)^{17} = 0$

$P(X = 4) = C_{20,4}.(0.96)^{4}.(0.04)^{16} = 0$

0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

A similar problem is given at brainly.com/question/24863377

8 0

3 years ago

Rewrite the equation by completing the square 4x^2-4x+1=0

oee [108]

Answer:

4(x - $\frac{1}{2}$ )² = 0

Step-by-step explanation:

Given

4x² - 4x + 1 = 0

To complete the square the coefficient of the x² term must be 1

Factor out 4 from 4x² - 4x

= 4(x² - x) + 1 = 0

add/subtract ( half the coefficient of the x- term )² to x² - x

4(x² + 2(- $\frac{1}{2}$ )x + $\frac{1}{4}$ - $\frac{1}{4}$ ) + 1 = 0

4(x - $\frac{1}{2}$ )² - 1 + 1 = 0

4(x - $\frac{1}{2}$ )² = 0

8 0

3 years ago

Read 2 more answers

A person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed th

dexar [7]

$\tan(51^o 33')= \frac{200}{base1}$

base1= 158.802

 $\tan(18^o 33')= \frac{200}{base2}$

base2=596.008

the distance travelled = 596.008 - 158.802 = 438 m

8 0

3 years ago