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svp [43]
4 years ago
7

Find the lengths of AB,BC,PQ,and QR. Which segments have equal lengths?

Mathematics
1 answer:
muminat4 years ago
3 0
I need the picture that goes with this problem
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If the initial amount of iodine-131 is 537 grams , how much is left after 10 days?
viktelen [127]

Answer:

225.78 grams

Step-by-step explanation:

To solve this question, we would be using the formula

P(t) = Po × 2^t/n

Where P(t) = Remaining amount after r hours

Po = Initial amount

t = Time

In the question,

Where P(t) = Remaining amount after r hours = unknown

Po = Initial amount = 537

t = Time = 10 days

P(t) = 537 × 2^(10/)

P(t) = 225.78 grams

Therefore, the amount of iodine-131 left after 10 days = 225.78 grams

4 0
3 years ago
The critical points of a rational inequality are –1, 3, and 4. Which set of points can be tested to solve the inequality? x = 1
never [62]

Answer:

x=-3, x=1, x=3.5, and x=5

Step-by-step explanation:

Given the critical points (turning points) which represent the maximum or the minimum points, the set of points that can be tested to solve the inequality will consist of points to the right and to the left of these points. The set of points that solve the inequality will be simply the points where the graph of the function crosses the x-axis. From these information, the set of points will be as given above

4 0
3 years ago
Read 2 more answers
Allison has 4 1/2 cups of sugar. She used 2/3 of it to make cookies. How much sugar did Allison use for the cookies?
solmaris [256]
Answer:

1 1/2 cups

Work: 2/3 of 4 1/2= 3
4 1/2-3= 1 1/2
7 0
3 years ago
Read 2 more answers
Solve for y please I have no clue I am so lost thank you
Inga [223]

In the Triangle ABD, Using Pythagoras theorem we can write

AB^2=BD^2+AD^2\\ \\ AB^2=9^2+y^2\\ \\ AB^2=81+y^2\\ \\

In the Triangle ACD using Pythagoras Theorem

AC^2=AD^2+CD^2\\ \\ AC^2=y^2+7^2\\ \\ AC^2=y^2+49\\

Now in the larger Triangle ABC, we can write

AB^2+AC^2=BC^2

Now substitute the values from the above equations we get

81+y^2+49+y^2=(9+7)^2\\ \\ 130+2y^2=16^2\\ \\ 130+2y^2=256\\ \\ 65+y^2=128\\ \\ y^2=128-65=63\\ \\ y=\sqrt{63} =3\sqrt{7} \\

3 0
3 years ago
Which rounding strategy will result in the most reasonable estimate for the expression −148+297+−546+151+48?
ArbitrLikvidat [17]

Answer:

-150 + 300 - 550 + 150 +50 = -200

Step-by-step explanation:

I rounded to the nearest tens place for each number.

8 0
3 years ago
Read 2 more answers
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