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-Dominant- [34]
3 years ago
8

What is 16.666666667 rounded to the nearest tenth

Mathematics
2 answers:
eimsori [14]3 years ago
8 0
16.666666667 rounded to the nearest tenth is 16.7. Rounded to the nearest "tenth" means rounded to one decimal place.
timurjin [86]3 years ago
6 0
<span>16.666666667 rounded to the nearest tenth is 16.7.</span>
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I need help please I don't understand it
german

Answer:

The third and the forth

Step-by-step explanation:

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Since the other options have doubles of an x value

(or, to phrase it differently, two y values for one x value)

they are not functions.

3 0
3 years ago
Question 5 (2) x cube - 3x square 9x - 5
kakasveta [241]
Please, post the instructions along with your question, and if possible share the question in symbolic form, not in words.

Do you mean Question #5?  By  (2) x cube, do you mean 2x^3?

I strongly suggest that you use lots of parentheses (   ) to show how your numbers are grouped, and not to use " x " to denote multiplication (use " * " for that, please.    

If only you'll clear this up, I'd be happy to help.

I will assume that your post is   2x^3 - 3(9x-5)^2.

Then 2x^3 - 3(81x - 90x + 25).  Does this have any resemblance to what you wanted me to see in your post?

3 0
3 years ago
How do i find the answer of this math question or problem f(x) = 4x − 9?
Mademuasel [1]

Answer:

x = 9/4

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6 0
2 years ago
(1+y) (4y+6) =0 algebra 2
marta [7]
Here is your answer! Hope this helped

5 0
3 years ago
Find a third-degree polynomial function with real coefficients and with zeros at -4 and -3 5i
Charra [1.4K]

If -3+5i is a solution, then by the conjugate root theorem, -3-5i is also a solution. We find the polynomial by multiplying together the factors. If x = -4, then x + 4 is the factor. If x = -3+5i, then (x-(-3+5i)) is a factor, and so is (x-(-3-5i)). Simplifying those down gives us as the first factor as (x+3-5i) and the second as (x+3+5i). We can FOIL those 2 together to get their product, and then FOIL in x+4. FOILing the 2 complex factors together gives us x^2+3x+15ix+3x+9+15i-15ix-15i-25i^2. If we combine like terms and cross out things that cancel it's much easier than what it looks like there! It simplifies down to x^2+6x-25i^2. Since i^2 = -1, it simplifies further to x^2+6x-25(-1) and finally, to x^2+6x+25. Now we will FOIL in x+4. (x^2+6x+25)(x+4)=x^3+6x^2+25x+4x^2+24x+100. Our final simplified third degree polynomial is x^3+10x^2+49x+100

3 0
4 years ago
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