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Nuetrik [128]
3 years ago
15

A rectangular parking lot has an area of 682 square yards.The lot is 22 yards wide.What is the length of the parking lot?

Mathematics
1 answer:
natta225 [31]3 years ago
7 0

Answer:

The  length of the parking lot is 31 yard .

Step-by-step explanation:

Formula

Area of a rectangle = Length × Breadth

As given

A rectangular parking lot has an area of 682 square yards.

The lot is 22 yards wide.

i.e Breadth = 22 yards

Put in the formula

682 = Length × 22

Length = \frac{682}{22}

Length = 31 yard

Therefore the  length of the parking lot is  31 yard .

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Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

(c) The probability that neither Dave nor Mike will show up is 0.25.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> =  Mike will show up.

Given:

P(D^{c})=0.55\\P(M^{c})=0.45

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

                                                   =1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0
3 years ago
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Answer:

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To cover a rectangular region of her yard, Penny needs at least 155 square feet of sod. The length of the
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<u><em>To cover a rectangular region of her yard, Penny needs at least 170.5 square feet of sod. The length of the region is 15.5 feet. What are the possible widths of the region?</em></u>

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<u><em>L=length=15.5 ft; W=width; A=area=>170.5 sq ft</em></u>

<u><em></em></u>

<u><em>L*W=>170.5 sq ft Divide each side by L</em></u>

<u><em></em></u>

<u><em></em></u>

<u><em>W=>170.5 sq ft/L</em></u>

<u><em></em></u>

<u><em>W=>170.5 sq ft/15.5 ft=>11 feet</em></u>

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ANSWER: To cover at least 170.5 sq ft. the width must be at least 11 feet.

<h2><em><u>Brainly pls</u></em></h2>

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