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3 years ago

El periodo de un movimiento circular uniforme es de 8 segundos. ¿Cuál es su velocidad angular?

Mathematics

1 answer:

11111nata11111 [884]3 years ago

7 0

Answer: I dont understand what your saying im sorry, I'd really like to help but I cant :(

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Aggie is an Australian exchange student in China, and she currently has 14,000 yuan in her bank account. If the exchange rate ch

Evgen [1.6K]

Find the value in Australian dollars for each exchange rate.
1st exchange rate: 
14000/6.21= $2254.43 

2nd exchange rate: 
14000/6.37= $2197.80 

Find the difference between the two: 
$2254.43 - $2197.80 = $56.63 

Since the first value is greater than your second one Aggie lost money and your answer is It decreases by $56.63.

3 0

3 years ago

Find the output, y, when the input, x, is 3. Y=-5x+13

Alexeev081 [22]

Answer:

y = -2

Step-by-step explanation:

y = -5x + 13

x = 3

y = -5(3) + 13

y = -15 + 13

y = -2

4 0

3 years ago

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suppose the solution x = 6 increases to x = 9, and the left side of the equation stays the same. How would the right side need t

PilotLPTM [1.2K]

X = 9 - 3, does this help?

7 0

4 years ago

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What is the quotient StartFraction 15 p Superscript negative 4 Baseline q Superscript negative 6 Baseline Over negative 20 p Sup

zhannawk [14.2K]

Answer:

$- \frac{3}{4} \times \frac{p^{8} }{q^{3} }$

Step-by-step explanation:

We have to find the quotient of the following division, $\frac{15p^{-4}q^{-6} }{- 20p^{-12} q^{-3}}$ .

Now, $\frac{15p^{-4}q^{-6} }{- 20p^{-12} q^{-3}}$

= $- \frac{3}{4} p^{[- 4 - (- 12)]} q^{[-6 - (- 3)]}$ {Since all the terms in the expression are in product form, so we can treat them separately}

{Since we know the property of exponent as $\frac{a^{b} }{a^{c} } = a^{(b - c)}$ }

= $- \frac{3}{4} p^{8} q^{-3}$

= $- \frac{3}{4} \times \frac{p^{8} }{q^{3} }$ (Answer)

{Since we know, $a^{-b} = \frac{1}{a^{b} }$ }

3 0

3 years ago

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I will give you 10B points plus mark someone again for the Brainliest if you get this right.

Musya8 [376]

Answer:

Option D is the correct answer

Step-by-step explanation:

$(3 {m}^{ - 4} )^{3} (3 {m}^{5} ) \\ \\ = {3}^{3} {m}^{ - 4 \times 3} \times 3 {m}^{5} \\ \\ = 27 \times 3 \times {m}^{ - 12 + 5} \\ \\ = 81 {m}^{ - 7} \\ \\ = \frac{81}{ {m}^{7} }$

8 0

4 years ago

Read 2 more answers