Answer:
We are given the path, y=-3x-6
The general form of the straight line is 'y=mx+b', where 'm' is the slope and 'b' is the y-intercept.
Thus, the slope of the given line is -3.
As, we have that the incipient path is perpendicular to the given path.
And, we ken that, 'Product of slopes of perpendicular lines is -1'.
Since, the incipient path passes through the point (-3,3). Superseding the values in the general form, we get,
b= 3+1
b= 4.
Step-by-step explanation:
