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Vsevolod [243]
3 years ago
9

What type of polygon would a slice of a hexahedron at a vertex create? Explain. What type of polygon would a slice of an icosahe

dron at a vertex create? Explain.

Mathematics
1 answer:
harina [27]3 years ago
3 0

Answer:

  • hexahedron: triangle or quadrilateral or pentagon
  • icosahedron: quadrilateral or pentagon

Step-by-step explanation:

<u>Hexahedron</u>

A hexahedron has 6 faces. A <em>regular</em> hexahedron is a cube. 3 square faces meet at each vertex.

If the hexahedron is not regular, depending on how those faces are arranged, a slice near a vertex may intersect 3, 4, or 5 faces. The first attachment shows 3- and 4-edges meeting at a vertex. If those two vertices were merged, then there would be 5 edges meeting at the vertex of the resulting pentagonal pyramid.

A slice near a vertex may create a triangle, quadrilateral, or pentagon.

<u>Icosahedron</u>

An icosahedron has 20 faces. The faces of a <em>regular</em> icosahedron are all equilateral triangles. 5 triangles meet at each vertex.

If the icosahedron is not regular, depending on how the faces are arranged, a slice near the vertex may intersect from 3 to 19 faces.

A slice near a vertex may create a polygon of 3 to 19 sides..

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Xander needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64 items.
Aleksandr [31]

Answer:

c ≥ 56   is the REQUIRED INEQUALITY.

Step-by-step explanation:

Here, the given  question is INCOMPLETE.

Xander needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64 items. Choose the inequality and solution to represent the number of cans, c, that Xander must still collect.

Now, here:

The number of cans Xander needed to collect = At least 120

The number of items already collected =  64

c: the number of cans, c, that Xander must still collect.

Now, the number of cans to be collected  - Cans already collected  

=  120 - 64  = 56

So, the number of can he must collect to make a TOTAL OF AT LEAST 120 cans  =  56 cans

⇒ The number of cans to be collected ≥ 56 cans

⇒c ≥ 56 cans

or, c ≥ 56   is the REQUIRED INEQUALITY.

3 0
3 years ago
Y = 3/2x + 5/4 −2x + 8y = −25
Andreyy89

Answer:

<h2>x = -347 1/2</h2>

Step-by-step explanation:

When solving algebra, it is important the we follow the steps in correct order and check our answer at the end.

Step 1: Simplify by combining like terms

y = -x/2 + 5/4 + 8y = -25

Step 2: Substitute

y = -25

-25 = -x/2 + 5/4 + 8(-25)

-25 = -x/2 + 5/4 + -200

-25 = -x/2 - 198 3/4

Step 3: Answer

x = -347 1/2

Step 4: Check

y = 3/2x + 5/4 −2x + 8y = −25

-25 = 3/2(-347 1/2) + 5/4 −2(-347 1/2) + 8(-25)

-25 = -25✔️

Step 5: Verified Answer

x = -347 1/2

I'm always happy to help :)

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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