80 sketches will be required. It’s just multiplication. Let x=boys and y=girls. If x=8 and y=10, then one boy has to be with one girl. In total 1 boy will be with 10 girls, so that’s 10 sketches. You do the same for boy #2 and so on. It adds up to 80.
Answer:
MIPS Code:
.data
newline: .asciiz "\n" #newline variable
.text
MAINLOOP:
li $v0, 5 #syscall to get user interger and store in $v0
syscall
add $a0, $zero, $v0 #moving the user input to $a0 from $v0
beq $a0, 0, EXIT #branching to EXIT when $a0 is 0
li $v0, 1 #syscall to print integer in $a0
syscall
li $v0, 4 #syscall to print newline
la $a0, newline
syscall
j MAINLOOP #jumping to MAINLOOP
EXIT:
Sample Output:
6
6
7
7
3
3
0
1. C) RAM
2. C) CPU
3. B) Accounts Payable
I believe these are the correct answers you are looking for.
Simple...
Although we are not allowed to link in websites..(against guidelines) you can search up codeacademy, this is a place to learn to code.
Thus, your answer.
