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stich3 [128]
3 years ago
8

A moving company wants to buy a new type of truck and needs to know the volume of the storage compartment before they can decide

if they should purchase the truck. What is the volume of the storage compartment?​
Mathematics
1 answer:
shutvik [7]3 years ago
6 0

Step-by-step explanation:

I think you should compare whatever you can do to your truck and pull

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What is the arc length of an arc with radius 10 in and central angle 60 degrees ? Show your work.
emmasim [6.3K]

Answer:

\huge \boxed{ \boxed{ \red{{s \approx \: 10.47}}}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • geometry
  • PEMDAS
<h3>tips and formulas:</h3>
  • s =  \frac{\pi {r} \theta}{180}
<h3>given:</h3>
  • r=10
  • \theta = 60
<h3>let's solve:</h3>
  1. \sf sustitute \: the \: value s \: of \:  \theta \: and \: r :  \\  =\frac{\pi \times 10 \times 60}{180}
  2. \sf rediuce \: 60 :  \\  =\frac{\pi \times 10 \times  \cancel{60}  \: ^{1} }{ \cancel{180}  \:  \:^{3} }  \\  =\frac{\pi \times 10}{3}
  3. \sf use \: 3.14 \: for \: \pi :  \\ = \frac{3.14 \times 10}{3}
  4. \sf simplify \: multipication :  \\  =  \frac{31.4}{3}  \\  \approx \: 10.47
5 0
3 years ago
" Pentagon ABCDE and pentagon A’B’C’D’E’ are shown on the coordinate plane below.
vampirchik [111]
<span>The answer: b. translated according to the rule (x, y) → (x + 8, y + 2) and reflected across the x-axis

If you make the drawing of the situation you realize the you need a reflection through the x-axis, but first you need to translate the polygon several units to the left and upward.

You can see that all the x-coordinates have increased 8 units, so the solution has to include x + 8.

Also, you see that you have to move the polygon 2 units upward before doing the reflection so the solution has to include y + 2.

So, the answer is (x,y) ---> (x + 8, y + 2) and then reflection across the x-axis.


</span>
6 0
3 years ago
Read 2 more answers
What are the possible lengths for x, the third side of a triangle, if two sides are 21 and 10
SashulF [63]
To solve we need to use Pythagoras theorem ( a^{2} +  b^{2} =  c^{2} )

There are 2 possible lengths for x: hypotenuse or one of the 2 shorter sides.

Hypotenuse:
10^{2} + 21^2 = x^{2}
100+441= x^{2}
\sqrt{541} =  \sqrt{ x^{2} }
23.3≈x

Shorter leg:
10^2 + x^2=21^2
x^2= 21^2-10^2
x^{2}= 441-100 
\sqrt{ x^{2} } = \sqrt{341}
x≈18.47
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3 years ago
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equation. this is the first equation

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