A = l x w
so you know that the length is 3m longer than the width, so you could use a formula to represent that
w = l + 3
you then substitute the second equation into the first to solve for l
70 = l x (l +3)
70 = l^2 + 3l
you could then rearrange the formula and solve for l using the quadratic formula
0 = l^2 + 3l - 70
l = -3 +- (square root (3)^2 - 4(1)(70)) / 2(1)
l = -3 +- (square root 9 + 280) / 2
l = -3 +- (square root 289) / 2
l = -3 +- 17 / 2
then you solve for the two seperate roots
l = -3 + 17 /2
l = 14 / 2
l = 7
or
l = -3 - 17 / 2
l = -20 / 2
l = -10
since a length cannot be negative, this root is not viable. therefore l = 7
to solve for w you would use
w = l + 3
w = 7 + 3
w = 10
hope this helps! if you did not understand a step or concept please let me know!
Answer:
The Last Option: Billy, Bonnie, Benny, Bobby
Step-by-step explanation:
Bobby = 8.3
Bonnie = 840%
=> 840/100
=> 8.4
(8.4^2 = 70.56)
Billy = Square root of 71
=> Square root of 71 is between 8 and 9.
=> 8.4^2 = 70.56. So, the square root of 71 must be a larger number than 8.4.
=> Square root of 71 is 8.426.
Benny = 8 1/3
=> 25/3
=> 8.3333333333
If we order these greatest to least:
=> 8.426, 8.4, 8.3333333333, 8.3
=> Billy, Bonnie, Benny, Bobby
Their is only one y for each x. you could also use the vertical line test, you could use the graphing calculator.
Answer:
m = 1
Step-by-step explanation:
We can suppose that the number we are looking for is for example 5.
(we can do so because the probability is the same for each number - it'sna fair dice)
For the first toss the probability we have 5 is 1/6 (we have 6 numbers on the dice and number 5 is just one of the possible 6 outcomes).
For the second toss the probability we have 5 is again 1/6.
For the rest of 3 tosses we don'tcare what number we will get( we have our two consecutive 5s), so all of the outcomes for the rest of 3 tosses are good for us (probability is 6/6 = 1)
Threfore, the probability to get two consecutive 5s is 1/6 * 1/6 * 1 * 1 * 1 = 1/36.
We can see that m = 1.
Answer:
G. 2/5
add the total amount of bows then find out of that much how many are purple