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dexar [7]
2 years ago
12

I need help fast thanks

Mathematics
1 answer:
BabaBlast [244]2 years ago
3 0

Answer:

I wanna say its all real numbers

Step-by-step explanation:

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Write the slope-intercept form of the equation through (4, 2) perpendicular to LaTeX: y=4x-4
marin [14]

Answer:

y=4x-4

slope of the line=-4/-1

                             4/1

since perpendicular,

    m1.m2=-1

    4.m2=-1

    m2=-1/4

The equation of line passing through the point (4,2)is

  y-y1=m2(x-x1)

  y-2=-1/4(x-4)

Step-by-step explanation:

i don't say that you have to mark my ans as brainliest but my friend if  it has helped you a bit also don't forget to thank me.....

3 0
3 years ago
Three less than 5 times a number is less than or equal to 12. If the number is a whole number, what could the number be?:
PIT_PIT [208]

Answer:

D

Step-by-step explanation:

4x2=8

5x2=10

6x2=12

This answer is the closest to 12 but it doesn't go over 12, so this is less than or equal to 12

8 0
3 years ago
Find the distance between the points L and D.<br><br>A)-2<br>B)0<br>C)1<br>D)2​
Alisiya [41]

Answer:

C) 1

there is only one space between L and D

8 0
3 years ago
If you understand, please put the answer!
il63 [147K]

Step-by-step explanation:

3-8 is diagnal 7-2 is also 7-2 is the answer

8 0
3 years ago
Write the equation of a line Parallel to the given line and passes through points (-4, -3); (2, 3). Hints find the slope by usin
julia-pushkina [17]

First, we obtain the gradient (slope) of the first parallel line

\text{gradient, m}_1\text{ = }\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{3-(-3)}{2-(-4)}=\frac{6}{6}\text{ = 1}

Recall that since both lines are parallel, we have that,

m_1=m_2

Thus

m_2\text{ = 1}

Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)

Using

\begin{gathered} y\text{ = mx + c} \\ \text{where m = m}_2\text{ = 1} \\ \text{and x = -4 ,  y = -3, we have} \\ -3\text{ = 1(-4) + c} \\ -3\text{ = -4 + c} \\ 4\text{ - 3 = c} \\ c\text{ = 1} \\ \text{Thus, the equation of the line is y = (1)x + 1} \\ y\text{ = x + 1} \end{gathered}

5 0
1 year ago
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