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aksik [14]
3 years ago
13

Complete this statement 20ax^2+25ax+15a=5a( )

Mathematics
1 answer:
tia_tia [17]3 years ago
3 0
Factor out 5a from the left side...

5a(4x^2+5x+3)=5a()

So 4x^2+5x+3 goes into the parentheses...
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Today Jason has 123 stamps in his collection. He got 5 stamps at a show last week. Then he got 4 more stamps at a show this week
lozanna [386]
114 stamps he had before
3 0
3 years ago
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The cost of providing water bottles at a high school football game is $35 for the rental of the coolers and $0.50 per bottle
zloy xaker [14]

The cost function is an illustration of a linear function

The equation of the cost function is C(x) = 35 + 0.5x

The given parameters are:

Rentals = 35 -- the cost of renting a cooler

Rate = 0.5 --- the rate per bottle

Assume the number of bottles in a cooler is x.

The cost function for the bottles in a cooler would be:

C(x) = Rentals + Rate \times x

So, we have:

C(x) = 35 + 0.5\times x

Evaluate the products

C(x) = 35 + 0.5x

Hence, the equation is C(x) = 35 + 0.5x

Read more about linear functions at:

brainly.com/question/15602982

7 0
2 years ago
Find simple interest on $5,523 principal deposited for seven years at a rate of 4.99%
Whitepunk [10]
I=PRT
I=interest
P=initial amount
R=rate in decimal
T=time in years

given
P=5523
R=4.99%=0.0499
T=7

I=(5523)(0.0499)(7)
I=1929.1839
round

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8 0
3 years ago
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You own three different rings. You wear all three rings, but no two of the rings are on the same finger, nor are any of them on
Eddi Din [679]

Answer:

Therefore you can wear your rings in =336 ways

Step-by-step explanation:

Multiplication Law: If one occurs in x ways and second event occurs in y ways.Then the number of ways that two event occur in sequence is xy

Given that you have 3 different rings.

We have total 10 figures.

But you don't wear ring on your thumbs.

We have 2 thumbs.

So you can wear rings on (10-2) = 8 figures.

The ways of wearing of first ring is = 8

The ways of wearing of second ring is = 7

The ways of wearing of third ring is = 6

Therefore you can wear your rings in =(8×7×6)

                                                             =336 ways

4 0
3 years ago
3x^5+6x^3<br><br> PRIME<br> b<br> 3x^4(3x + 2)<br> 3(x^5 + x^3)<br> d<br> 3x^3(x^2 + 2x)
Gelneren [198K]

Answer:

Im guessing 33(2+2)

8 0
2 years ago
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