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Soloha48 [4]
3 years ago
8

HELPPP THIS IS DUE SOON! I WILL MARK BRAINLIEST

Mathematics
2 answers:
sammy [17]3 years ago
6 0
What he just did ^^^
expeople1 [14]3 years ago
4 0

Answer:

7.3

Step-by-step explanation:

For this question, you must use the distance formula. The distance formula is based around Pythagorean Theorem, so you will see some similarities.

Distance = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

X2 is 7 (X coordinate of school)

X1 is 5 (X coordinate of friend's house)

7 - 5 = 2

2^2 = 4

Y2 is 7 (Y coordinate of school)

Y1 is 0 (Y coordinate of friend's house)

7 - 0 = 7

7^2 = 49

4 + 49 = 53

\sqrt{53} = 7.2801...

<em>Round to the nearest tenth...</em>

<em>7.3</em>

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HELP ASAP ITS SO HARD! Kelsey did the following division problem. Her teacher says that the quotient she found is wrong. −2 5/6
SpyIntel [72]

Part A

Her steps were

-2 \frac{5}{6} \div 1 \frac{1}{3}\\\\-\frac{17}{6} \div \frac{4}{3}\\\\-\frac{6}{17} \times \frac{3}{4}\\\\-\frac{6\times 3}{17\times4}\\\\-\frac{18}{68}\\\\-\frac{9}{34}\\\\

Kelsey made a mistake on line 3. Note how the 17/6 flips to 6/17. This is not correct. You keep the first fraction the same, but you do flip the second fraction. This only applies when you divide two fractions.

The third step should look like -\frac{17}{6}\times \frac{3}{4}

=======================================================

Part B

Here's what she should have written

-2 \frac{5}{6} \div 1 \frac{1}{3}\\\\-\frac{17}{6} \div \frac{4}{3}\\\\-\frac{17}{6} \times \frac{3}{4}\\\\-\frac{17\times 3}{6\times 4}\\\\-\frac{51}{24}\\\\-\frac{17}{8}\\\\

If you want to convert that improper fraction to a mixed number, then you could do something like this

-\frac{17}{8} = -\frac{16+1}{8}\\\\-\frac{17}{8} = -\frac{16}{8}-\frac{1}{8}\\\\-\frac{17}{8} = -2 \frac{1}{8}\\\\

Or you could divide 17 over 8 using long division to get 2 remainder 1. The 2 is the quotient that goes to the left of the 1/8. The remainder of 1 is the numerator of 1/8.

4 0
3 years ago
Read 2 more answers
The measure of an exterior angle at n measures 99�. m�l � __1 3 x� and m�m � __2 3 x�. find m�l, m�m, and m�lnm.
kirill [66]
You should ask your parent/guardian
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8 0
4 years ago
Please help with these
kherson [118]

The answers are as follows.

a. 9x

In order to get this, you need to reevaluate 64 as a base of 4. Since 64 is equal to 4^3, we can rewrite the right side as

64^3x = (4^3)^3x = 4^9x

Which gives you the first answer.

b. 10

Similar to the first problem, we need to express 16 as a base of 2. 2^4 is equal to 16, so we use that in it's place and simplify.

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4 0
3 years ago
Solve for x.
denis-greek [22]

Answer:

\frac{3\±\sqrt{3}}{3}

Step-by-step explanation:

Whe have the function 3x^2-6x+2=0

To solve this equation we must factor.

To factor, we need to find the points where the function is equal to zero. So we use the quadratic formula

\frac{-b\±\sqrt{b^2-4ac}}{2a}

Where:

a = 3

b = -6

c = 2

Then

\frac{-(-6) + \sqrt{(-6)^2-4(3)(2)}}{2(3)} = \frac{3+\sqrt{3}}{3}\\\\and\\\\\frac{-(-6) - \sqrt{(-6)^2-4(3)(2)}}{2(3)}= \frac{3-\sqrt{3}}{3}

finally the correct answer is  \frac{3\±\sqrt{3}}{3}

5 0
3 years ago
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I need help I'm not so good with geometry
cricket20 [7]
What's C and A mean?
5 0
3 years ago
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