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3 years ago

HELPPP THIS IS DUE SOON! I WILL MARK BRAINLIEST

Mathematics

2 answers:

sammy [17]3 years ago

6 0

What he just did ^^^

expeople1 [14]3 years ago

4 0

Answer:

7.3

Step-by-step explanation:

For this question, you must use the distance formula. The distance formula is based around Pythagorean Theorem, so you will see some similarities.

Distance = $\sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}$

X2 is 7 (X coordinate of school)

X1 is 5 (X coordinate of friend's house)

7 - 5 = 2

2^2 = 4

Y2 is 7 (Y coordinate of school)

Y1 is 0 (Y coordinate of friend's house)

7 - 0 = 7

7^2 = 49

4 + 49 = 53

$\sqrt{53}$ = 7.2801...

Round to the nearest tenth...

7.3

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Find the standard form polynomial that represents this product. (6 - y - 4y^2)(-5 + 7y^2)

Tema [17]

Answer:

-28y^4 - 7y^3 + 62y^2 + 5y - 30

Step-by-step explanation:

Opening the parenthesis and simplifying by combining like terms:

(6 - y - 4y^2)(-5 + 7y^2) =
6(-5) +6(7y^2) - y(-5) -y(7y^2) -4y^2(-5) -4y^2(7y^2) =
-30 + 42y^2 + 5y - 7y^3 +20y^2 -28y^4 =
-28y^4 - 7y^3 + 62y^2 + 5y - 30

5 0

3 years ago

The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f

Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

$h(t)=-16t^{2}+25t+5$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

$h(t)=-16(t^{2}-\frac{25}{16}t)+5$

Complete the square

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}$

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}$

Rewrite as perfect squares

$h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

The vertex is the point $(\frac{25}{32},\frac{945}{64})$

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

$0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

$16(t-\frac{25}{32})^{2}=\frac{945}{64}$

$(t-\frac{25}{32})^{2}=\frac{945}{1,024}$

square root both sides

$(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}$

$t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}$

the positive value is

$t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec$

8 0

3 years ago

How many solutions does x²+3x=3 have?

aev [14]

Answer:

2 (real) solutions.

Step-by-step explanation:

A quadratic always has two solutions, whether they are real or complex.

Sometimes the solution is complex, involving complex numbers (2 complex), sometimes they are real and distinct (2 real), and sometimes they are real and coincident (still two real, but they are the same).

In the case of

x^2+3x = 3, or

x² + 3x -3 = 0

we apply the quadratic formula to get

x = (-3 +/- sqrt(3^2+4(1)(3))/2

to give the two solutions

{(sqrt(21)-3)/2, -(sqrt(21)+3)/2,}

both of which are real.

4 0

3 years ago

Given the following functions f(x) and g(x), solve (f+g)(2) and select the correct answer below:

Anika [276]

Answer:

Step-by-step explanation:

In the picture above

Hope this helps.

3 0

4 years ago

You are driving home on a weekend from school at 55 mi/h for 110 miles. it then starts to snow and you slow to 35 mi/h. you arri

stepladder [879]

Okay lets get started.

I drove 110 miles with speed of 55 mi/hr so the time taken =

time = distance / speed

time = 110 / 55 = 2 hrs For the distance which is covered with 55 mi/hr speed.

Total time for reaching home is 4 hrs 15 minutes. (given in question)

Means rest distance after snow is covered in = 4 hrs 15 minutes - 2 hrs

= 2 hrs 15 minutes = 2 + 15/60 = 2.25 hrs

The speed in snow driving is 35 mi/hr

So distance covered in snow driving is = 2.25 * 35 = 78.75 miles

Hence the total distance = 110 + 78.75 = 188.75 miles : Answer

Hope that will help :)

6 0

3 years ago